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VMariaS [17]
3 years ago
7

Manganese (IV) nitride formula

Chemistry
1 answer:
stepan [7]3 years ago
7 0

Answer:

Mg(NO3)2 is the formula of manganese (IV) nitride.

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__is when two genetic sequences bind together because of the hydrogen bonds that form between the base pairs ​
Anettt [7]

Answer:

I would say that it is the bond called complementary hydrogen bonds

Explanation:

The nucleotides in a base pair are complementary which means their shape allows them to bond together with hydrogen bonds. The A-T pair forms two hydrogen bonds. The C-G pair forms three. The hydrogen bonding between complementary bases holds the two strands of DNA together.

6 0
4 years ago
Most adult amphibians can obtain oxygen through?
Rina8888 [55]
Their skin absorbs oxygen

4 0
3 years ago
What is the property that is most similar among all elements across a whole period called
taurus [48]
The atomic mass........
4 0
3 years ago
A 33.153 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap
elena-14-01-66 [18.8K]

Answer:

The empirical formula of the compound = C_4H_8S_1O_1

Explanation:

Mass of carbon dioxide gas = 59.060 mg = 0.059060 g

1 mg = 0.001 g

Moles of carbon dioxide = \frac{0.059060 g}{44 g/mol}=0.0013 mol

Moles of carbon in 0.0013 moles of carbon dioxide gas = 1 × 0.0013 mol = 0.0013 mol

Mass of 0.0013 moles of carbon = 12 g/mol\times 0.0013 mol=0.0156 g

Mass of water = 24.176 mg = 0.024176

Moles of water = \frac{0.024176 g}{18 g/mol}=0.0013 mol

Moles of hydrogen in 0.0013 moles of water = 2 × 0.0013 mol = 0.0026 mol

Mass of 0.0013 moles of hydrogen= 1 g/mol\times 0.0013 mol=0.0013 g

Mass of sulfur dioxide = 20.326 mg = 0.020326 g

Moles of sulfur dioxide = \frac{0.020326 g}{64 g/mol}=0.00032 mol

Moles of sulfur in 0.00032 moles of sulfur dioxide = 1 × 0.00032 mol = 0.00032 mol

Mass of 0.00032 moles of sulfur = 32 g/mol\times 0.00032 mol=0.01024 g

Mass of oxygen in the sample = x

Mass of sample = 33.153 mg = 0.033153 g

0.033153 g = 0.0156  g + 0.0013 g + 0.01024 g + x

x = 0.006013 g

Moles of oxygen = \frac{0.006013 g}{16 g/mol}=0.00038 mol

For empirical formula divide the lowest number of moles of elemnt from all the moles of the all the elements:

Carbon : \frac{0.0013 mol}{0.00032 mol}=4

Hydrogen: \frac{0.0026 mol}{0.00032 mol}=8

Sulfur : \frac{0.00032 mol}{0.00032 mol}=1

Oxygen : \frac{0.00038 mol}{0.00032 mol}=1

The empirical formula of the compound = C_4H_8S_1O_1

8 0
4 years ago
Which of the following correctly describes a compound
Reptile [31]

combination of elements on the periodic table to create a substance. so I think I understand about this okay but I have a 98% on that type of subject

8 0
3 years ago
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