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Harman [31]
3 years ago
11

A mass spectrum of an organic compound shows the relative abundances of M to be 40.58% and M 1 to be 7.022%. Assuming the peaks

are caused by 12C and 13C isotopes, determine the number of carbon atoms in the compound. Natural abundances: 12C is 98.93% and 13C is 1.07%
Chemistry
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

The number of carbon atoms in the organic compound is 16.

Explanation:

The relative intensity of M + 1 peak (relative to M = 100) in organic compounds can be predicted by the following formula:

[M + 1] = (number of C x 1.07) ---------------------------------------------------- (1)

This formula can also be used to determine the number of carbon from the given intensity. But first, the intensity of [M + 1] relative to [M] = 100 needs to be determined, for which, consider the following calculations,

[M+1]=(\frac{M+1}{M}) (100)

[M+1]=(\frac{7.022}{40.58}) (100)

[M+1]=17.30

Using equation 1 we get,

number of C=\frac{[M+1]}{1.07}

number of C=\frac{17.3}{1.07}\\number of C = 16.168

or number of C = 16

The remaining value, 0.168, can be due to the isotopes of hydrogen and oxygen in the organic compound.

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Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio
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PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

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4 0
2 years ago
What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?
Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

 The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

                           H = 1g/mol

                            N = 14g/mol

                            O = 16g/mol

 Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

                                = 168 + 22 + 56 + 128

                                 = 374u

Empirical weight:

  Empirical formula:

                        C₁₄    H₂₂      N₄     O₈

                         14  :    22 :    4  :     8

   divide by 2:

                          7   :    11    :    2  :    4

     empirical formula  C₇H₁₁N₂O₄

     empirical weight = \frac{molecular weight}{2} = \frac{374}{2} = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

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