Answer:
2800 g de ácido nítrico
Explanation:
La ecuación por la oxidación de amoniaco es:
4NH₃ + 7O₂ → 4H₂O + 2HNO₂ + 2HNO₃
Si pensamos que el oxígeno es el reactivo limitante, trabajamos con el amoniaco. Convertimos su masa a moles:
1.36 kg = 1360 g
1360 g . 1mol /17g = 80 moles
Si 4 moles de amoniaco pueden producir 2 moles de acido nítrico
80 moles producirán, (80 . 2)/4 = 40 moles.
Convertimos los moles a gramos:
40 mol . 63g /mol = 2520 g
Si le aplicamos la pureza
2520 g . 100/90 = 2800 g
A) LiAlH4
b) Ph(3)SnH
c)Na in dry ether(Wurtz reaction)
Answer:
![K_{goal}=1.793*10^{-33}](https://tex.z-dn.net/?f=K_%7Bgoal%7D%3D1.793%2A10%5E%7B-33%7D)
Explanation:
N2(g)+O2(g)⇌2NO(g), ![K_1 = 4.10*10^{-31}](https://tex.z-dn.net/?f=K_1%20%3D%204.10%2A10%5E%7B-31%7D)
N2(g)+2H2(g)⇌N2H4(g), ![K_2 = 7.40*10^{-26}](https://tex.z-dn.net/?f=K_2%20%3D%207.40%2A10%5E%7B-26%7D)
2H2O(g)⇌2H2(g)+O2(g), ![K_3 = 1.06*10^{-10}](https://tex.z-dn.net/?f=K_3%20%3D%201.06%2A10%5E%7B-10%7D)
If we add above reaction we will get:
2N2(g)+2H2O(g)⇌2NO(g)+N2H4(g) Eq (1)
Equilibrium constant for Eq (1) is ![K_1*K_3*K_3](https://tex.z-dn.net/?f=K_1%2AK_3%2AK_3)
Divide Eq (1) by 2, it will become:
N2(g)+H2O(g)⇌NO(g)+1/2N2H4(g) Eq (2)
Equilibrium constant for Eq (2) is ![(K_1*K_3*K_3)^{1/2}](https://tex.z-dn.net/?f=%28K_1%2AK_3%2AK_3%29%5E%7B1%2F2%7D)
![Equilibrium constant =K_{goal}= (K_1*K_2*K_3)^{1/2}\\K_{goal}= (4.10*10^{-31} *7.40*10^{-26}*1.06*10^{-10})^{1/2}\\K_{goal}=1.793*10^{-33}](https://tex.z-dn.net/?f=Equilibrium%20constant%20%3DK_%7Bgoal%7D%3D%20%28K_1%2AK_2%2AK_3%29%5E%7B1%2F2%7D%5C%5CK_%7Bgoal%7D%3D%20%284.10%2A10%5E%7B-31%7D%20%2A7.40%2A10%5E%7B-26%7D%2A1.06%2A10%5E%7B-10%7D%29%5E%7B1%2F2%7D%5C%5CK_%7Bgoal%7D%3D1.793%2A10%5E%7B-33%7D)
Yes, it mixes it and has vitamins in the tea.
Complete balanced equation: 2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O
Ionized equation (with spectator ions):
2H⁺ + 2NO₃⁻ + Ca²⁺ + 2OH⁻ → Ca²⁺ + 2NO₃⁻ + 2H₂O
By eliminating the ions that are the same of both sides of the equation (spectator ions):
2H⁺ + 2OH⁻ → 2H₂O [Net Ionic Equation]