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zzz [600]
2 years ago
9

Which statement is correct?

Mathematics
1 answer:
Oksanka [162]2 years ago
6 0

Answer: D

Step-by-step explanation:

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What 2 numbers multiply to -18 and add up to -4
ivann1987 [24]

Answer:

-9 x 1 x 1 x 1 x 2 = (-18)

-9 + 1 + 1 + 1 + 2 = (-4)

5 0
3 years ago
What is the derivative of y with respect to x if y = 2/X4
zepelin [54]
You're correct, the answer is C.

Given any function of the form y=x^n, then the derivative of y with respect to x (\frac{dy}{dx}) is written as:
\frac{dy}{dx}=nx^n^-^1

In which n is any constant, this is called the power rule for differentiation.

For this example we have y= \frac{2}{x^4}, first lets get rid of the quotient and write the expression in the form y=x^n:
y= \frac{2}{x^4} =2x^-^4

Now we can directly apply the rule stated at the beginning (in which n=-4):
\frac{dy}{dx}=(2)(-4)x^{-4-1}=-8 x^{-5}= -\frac{8}{x^5}

Note that whenever we differentiate a function, we simply "ignore" the constants (we take them out of the derivative).
6 0
3 years ago
find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
2 years ago
A worker at a mill is loading 5-lb bags of flour into boxes to deliver to a local warehouse. Each box holds 8 bags of flour. If
Kitty [74]
10 bags of flour on fulfill
5 0
3 years ago
Y-intercept = (0, 2)<br> slope = -3/7 what is the equation?
Marianna [84]

Answer:

y = -(3/7)x + 2

Step-by-step explanation:

(see attached)

recall that the slope-intercept form of a linear equation is

y = mx + b

where m = slope = given as -(3/7)

and b = y-intercept = 2

substituting these values into the eqation:

y = mx + b

y = -(3/7)x + 2

8 0
3 years ago
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