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2 years ago

Work out the area of the tile.

Mathematics

1 answer:

zzz [600]2 years ago

5 0

Answer:

190 cm²

Step-by-step explanation:

Use the area of a trapezium formula: $\frac{1}{2} (a+b)h$

where a and b are the top and bottom bases, and h is the height.

Therefore,

area = $\frac{1}{2}\times (12+26)\times10$ = 190 cm²

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100 is the regular price if you buy one and get the other half price. Explain how this different from getting a 50% discount?

Vinvika [58]

100 = x + x/2

3x/2 = 100

x = 200/3

if there was 50% discount:

buying 1 would be $33.33

buying 2 would be $66.67

4 0

2 years ago

I need help with these questions ( see image for question ).<br>Please show working.<br>

antiseptic1488 [7]

Answer:

k = -4 ± 2√5

Step-by-step explanation:

#22

<h3>Given </h3>

Equation x² -4x + 1 = k(x - 4) with equal roots

The value of k

<h3>Solution</h3>

<u>The equation in standard form is:</u>

x² -4x + 1 = k(x - 4)
x² - 4x - kx + 1 + 4 = 0
x² - (k + 4)x + 5 = 0

<u>When the quadratic equation has equal roots its discriminant is zero</u>

D = 0
b² - 4ac = 0
(k + 4)² - 4*5 = 0
(k + 4)² = 20
k + 4 = ± √20
k = - 4 ± √20
or
k = -4 ± 2√5

5 0

2 years ago

A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

<u>the answer Part a) is</u>

the speed is equal to $3.5\frac{m}{sec}$

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

<u>the answer Part b) is</u>

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

$a=-\frac{7}{30}\frac{m}{sec^{2}}$

therefore

<u>the answer Part c) is</u>

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

7 0

3 years ago

Read 2 more answers

Point B is at (4, 5). It is reflected on the x-axis. What are the coordinates of its image, B'?

seropon [69]

Answer: (4, -5)

(so it sendswfegrgnhernth4retn)

4 0

2 years ago

BRAINLIEST + 20 POINTS!!!!!!!!!!!! THANKS AND 5 STAR RATING!!!!!!!!!!!

vesna_86 [32]

Answer:

3 and 5/16

Step-by-step explanation:

3+(2+8)2-:4*((1)/(2))^(4)=53/16

3 0

2 years ago