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Vinvika [58]
3 years ago
15

Find the cosine of ∠J.

Mathematics
1 answer:
Luden [163]3 years ago
7 0

Answer:

\cos =  \frac{base}{hypotenuse}  =   \\ \cos(j)  =  \frac{ \sqrt{29} }{ \sqrt{94} }    =   \sqrt{ \frac{29}{94} }  \\ answer =  \sqrt{ \frac{29}{94} }

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This is due today plz help
dybincka [34]

Answer:

how to answer it where is the direction

3 0
3 years ago
Production of a gas flow meter takes place in two distinct operations. Measurements (n = 15) of the time required for the first
Karolina [17]

Answer:

a) P(a > 80) = 0.323

b) The 95% confidence interval = (73.40, 80.60)

c) The 95% confidence interval expresses that the mean of the distribution can always be found in the given range, with a 95% confidence level.

Step-by-step explanation:

X ~ (45, 4)

Y ~ (32, 2.5)

(X+Y) ~ (77, 6.5)

Let a = (X+Y)

a) Probability that the time required to complete both of those steps will exceed 80 min = P(a > 80)

This is a normal distribution problem

We then standardize 80 min time

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (a - μ)/σ = (80 - 77)/6.5 = 0.46

To determine the probability the time required to complete both of those steps will exceed 80 min = P(a > 80) = P(z > 0.46)

We'll use data from the normal probability table for these probabilities

P(a > 80) = P(z > 0.46) = 1 - P(z ≤ 0.46) = 1 - 0.677 = 0.323

b) 95% confidence interval for the expected total time required to produce one flow meter.

We need to obtain the margin of error

Margin of error = (critical value) × (standard error of the sample)

Critical value for a 95% confidence interval = critical value for a significance level of 5% = t(15-1, 0.05/2) = 2.145 (using the t-score since information on the population mean and standard deviation isn't known)

Standard error for the sample of sum of times = (standard deviation of the sum of times)/√n = (6.5/√15) = 1.678

Margin of error = 2.145 × 1.678 = 3.60

Limits of the confidence interval = (Sample mean ± margin of error)

Lower limit of the confidence interval = (Sample mean - margin of error) = 77 - 3.60 = 73.40

Upper limit of the confidence interval = 77 + 3.60 = 80.60

The confidence interval = (73.40, 80.60)

4 0
3 years ago
PLEASE HELP!! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the trigonometric rat
Monica [59]

this is the answer on edmentum

6 0
3 years ago
Simplify the expression 9w+w+5w
loris [4]
15w
the answer is 15 w.
add 9+1+5
4 0
3 years ago
Read 2 more answers
Which of the following theorems verifies that ABC~WXY?
Bumek [7]

Answer:

The correct answer is option <em>B. AA</em>

<em></em>

Step-by-step explanation:

Given two triangle:

\triangle ABC  and \triangle WXY.

The dimensions given in \triangle ABC are:

\angle A = 27^\circ\\\angle B = 90^\circ

We know that the sum of three angles in a triangle is equal to 180^\circ.

\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 27+90+\angle C=180^\circ\\\Rightarrow \angle C = 63^\circ

The dimensions given in \triangle WXY are:

\angle Y = 63^\circ\\\angle X = 90^\circ

We know that the sum of three angles in a triangle is equal to 180^\circ.

\angle W+\angle X+\angle Y = 180^\circ\\\Rightarrow \angle W+90+63=180^\circ\\\Rightarrow \angle W = 27^\circ

Now, if we compare the angles of the two triangles:

\angle A = \angle W = 27^\circ\\\angle B = \angle X= 90^\circ\\\angle C = \angle Y= 63^\circ

So, by AA postulate (i.e. Angle - Angle) postulate, the two triangles are similar.

\triangle ABC \sim \triangle WXY by <em>AA theorem.</em>

<em>So, correct answer is option B. AA </em>

7 0
3 years ago
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