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spayn [35]
2 years ago
14

Find the values of x and y in the triangle below. (Please hurry)

Mathematics
1 answer:
NikAS [45]2 years ago
4 0

Answer:

x = 10.4

y = 9

Step-by-step explanation:

Suppose the triangles are similar

x/26 = 8/20 (side lengths must be proportional) cross multiply expressions

20x = 208 divide both sides by 20

x = 10.4

same goes for y

6/(6+y) = 8/20 cross multiply expressions

120 = 8y + 48 subtract 48 from both sides

72 = 8y divide both sides by 8

9 = y

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The probability of an event
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d. is the sum of the probabilities of the sample points in the event.

Step-by-step explanation:

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What is the area of the composite figure whose vertices have the following coordinates? (−2, −2) , (3, −2) , (5, −4) , (1, −8) ,
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Caroline opens a savings account at her local
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3 years ago
An object is launched into the air. The projectile motion of the object can be modeled using the function h(t) = –16t2 + 72t + 5
vladimir2022 [97]

Answer:

Step-by-step explanation:

In the equation, 72t represents the initial upwards velocity and 5 represents the initial launching height.  The leading term represents the pull of gravity on the object in the English system of measurement.

So the first question says the initial height is 5 feet.  TRUE

The second question says the initial vertical velocity is -72.  FALSE (it's positive 72 ft/sec)

The third question says that the object will hit the ground after approximately 4.57 seconds.  TRUE.  Find this by setting the h(t) on the left equal to 0, since this is the height at any time during the flight.  When h(t) = 0, that means that there is NO height, which means the object is on the ground.  Set the equation equal to 0 and factor to find t.  Putting that into the quadratic formula gives you t values of -.068 and 4.57.  Since the 2 things in math that will NEVER EVER be negative are distances and time, we can safely disregard the negative t value and go with t = 4.57.

The fourth question says that after t = 3 seconds, the object is 173 feet high.  FALSE.  Find this by subbing in a 3 for every t in the equation.

h(3)=-16(3)^2+72(3)+5

This gives you that h(3) = 77 feet

The last question says that at t = 0, h(t) = 0.  FALSE again.  Sub in a 0 for every t in the equation, and you get h(0) = 5, which is the initial launching height.

7 0
3 years ago
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