Correct answer is
D. 4.032 g of Hydrogen atoms contain same number of atoms as that contained by 2 moles of hydrogen molecules. Solution is below,
We can see from the details below that, the value of the solution's molality is 1.14 mol/Kg.
<h3>What is solubility?</h3>
The term solubility has to do with the quantity of solute that is able to dissolve in a given quantity of solvent. We have the solubility of the sodium hydrogen carbonate in water at 20 degrees as 9.6 g/100 g h2o.
Number of moles of sodium hydrogen carbonate = 9.6 g/84 g/mol = 0.114 moles
Number of moles water = 100 g /18 g/mol = 5.55 moles
Mole fraction of sodium hydrogen carbonate is obtainable by the use of the relation;
0.114 moles/0.114 moles + 5.55 moles
= 0.02
Molality of the solution = 0.114 moles/0.1 Kg = 1.14 mol/Kg
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In my opinion, a substance can be pure if it has unique properties through which it can be distinguished
Explanation:
When we add chlorine to a substance or compound then this process is known as chlorination.
For example, a process of chlorination is as follows.
Initiation :
where, Cl* is a free radical.
Propagation:
![Cl* + CH_{4} \rightarrow HCl + *CH_{3}](https://tex.z-dn.net/?f=Cl%2A%20%2B%20CH_%7B4%7D%20%5Crightarrow%20HCl%20%2B%20%2ACH_%7B3%7D)
![CH_{3} + Cl_{2} \rightarrow CH_{3}Cl + Cl*](https://tex.z-dn.net/?f=CH_%7B3%7D%20%2B%20Cl_%7B2%7D%20%5Crightarrow%20CH_%7B3%7DCl%20%2B%20Cl%2A)
Termination:
![2Cl* \rightarrow Cl_{2}](https://tex.z-dn.net/?f=2Cl%2A%20%5Crightarrow%20Cl_%7B2%7D)
![Cl* + *CH_{3} \rightarrow CH_{3}Cl](https://tex.z-dn.net/?f=Cl%2A%20%2B%20%2ACH_%7B3%7D%20%5Crightarrow%20CH_%7B3%7DCl)
![2*CH_{3} \rightarrow CH_{3}-CH_{3}](https://tex.z-dn.net/?f=2%2ACH_%7B3%7D%20%5Crightarrow%20CH_%7B3%7D-CH_%7B3%7D)
Thus, we can conclude that out of the given options
is not formed through a termination reaction in the chlorination of methane.