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vampirchik [111]
3 years ago
15

The pressure of a 5.0 L sample of gas changes from 3.0 atm to 10.0 atm while the temperature remains constant. What is the gas’s

new volume?
Chemistry
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

<h2>The answer is 1.5 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{5 \times 3}{10}  =  \frac{15}{10}  =  \frac{3}{5}  \\

We have the final answer as

<h3>1.5 L</h3>

Hope this helps you

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Which class of compounds contains only carbon, hydrogen, and nitrogen?
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Nitrogen forms many thousands of organic compounds. Most of the known varieties may be regarded as derived from ammonia, hydrogen cyanide, cyanogen, and nitrous or nitric acid. The amines, amino acids, and amides, for example, are derived from or closely related to ammonia.

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A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate
AlladinOne [14]

The given question is incomplete. The complete question is as follows.

A solution contains an unknown mass of dissolved barium ions. When sodium sulfate is added to the solution, a white precipitate forms. The precipitate is filtered and dried and then found to have a mass of 212 mg. What mass of barium was in the original solution? (Assume that all of the barium was precipitated out of solution by the reaction.)

Explanation:

When Ba^{2+} and Na_{2}SO_{4} are added  then white precipitate forms. And, reaction equation for this is as follows.

       Ba^{2+} + SO^{2-}_{4} \rightarrow BaSO_{4}

It is given that mass (m) is 212 mg or 0.212 g (as 1 g = 1000 mg). Molecular weight of BaSO_{4} is 233.43.

Now, we will calculate the number of moles as follows.

  No. of moles = mass × M.W

                        = \frac{0.212}{233.43}

                        = 0.00091 mol of BaSO_{4}

Hence, it means that 0.00091 mol of Ba^{2+}. Now, we will calculate the mass as follows.

       Mass = moles × MW

                 = 0.00091 \times 137.327

                 = 0.124 grams or 124 mg of barium

Thus, we can conclude that mass of barium into the original solution is 124 mg.

8 0
3 years ago
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