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kvv77 [185]
3 years ago
12

Which gas will diffusion faster within a system?

Chemistry
1 answer:
kifflom [539]3 years ago
3 0

Answer:

Methane(CH₄).

Explanation:

  • Thomas Graham found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

<em>∨ ∝ 1/√M.</em>

where, ∨ is the rate of diffusion of the gas.

M is the molar mass of the gas.

<em>∨₁/∨₂ = √(M₂/M₁)</em>

<em></em>

  • The molar mass of different choices:

Carbon dioxide: 44.01 g/mol.

Water vapor : 18.0 g/mol.

Ammonia (NH₃): 17.0 g/mol.

Methane(CH₄): 16.0 g.mol.

<em>Since, methane has the lowest molar mass. So, it will diffuse faster within a system.</em>

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amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

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3 years ago
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Answer:Noble gases:

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Explanation:Noble gases:

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According to Le Châtelier's principle, what happens if heat is added to a system? apex
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This change will partly counter acts the applied change.

Therefore, when heat is added to the system then equilibrium will shift to the side where temperature or heat is reduced again.

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Since heat is added to the system, hence, system will shift to the left side or we can say equilibrium will shift to the backward direction.

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Answer:

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N/No = (1/2)^5(t1/2)/t1/2

Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;

N/No= (1/2)^5

N/No = 1/32

Hence the fraction left is 1/32 of the original sample.

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