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e-lub [12.9K]
2 years ago
13

electric field lines point in the opposite direction WHAT charges would move if they were in the field

Physics
1 answer:
Neko [114]2 years ago
6 0

Answer:

Negative

Explanation:

hope i helped

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A runner is training and runs past meter mark 65 and starts a stopwatch. After the runner passes meter mark 15 the stopwatch sto
denis-greek [22]

Answer:

6.25 m/s

Explanation:

Given parameters

Initial mark = 65

Final mark  = 15

time taken = 8s

Unknown:

Velocity of the runner  = ?

Solution:

Velocity is the displacement divided by time;

        Velocity  = \frac{displacement}{time}  

Displacement  = Initial mark - final mark  = 65 - 15 = 50m

Now, insert the parameters and solve;

       Velocity  = \frac{50}{8}   = 6.25m/s

7 0
3 years ago
A positive charge of 8.0 × 10-4 C is in an electric field that exerts a force of 3.5 × 10-4 N on it. What is the strength of the
Gennadij [26K]

Answer:

E = 0.437 N/C

Explanation:

Given that,

Charge, q=8\times 10^{-4}\ C

Electric force, F=3.5\times 10^{-4}\ N

Let the strength of the electric field is E. We know that, the electric force is given by :

F = qE

Where

E is the electric field strength

E=\dfrac{F}{q}\\\\E=\dfrac{3.5\times 10^{-4}}{8\times 10^{-4}}\\E=0.437\ N/C

So, the strength of the electric field is equal to 0.437 N/C.

6 0
3 years ago
Calculate the acceleration of a bus whose speed changes from 6 m/s to 12 m/s over a period of 3s.
GenaCL600 [577]

Your answer would be 2.

8 0
4 years ago
1. The coin remains at rest in the figure shown. This is due to
sleet_krkn [62]
D would be correct.

Have a merry Christmas!
8 0
3 years ago
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To strike or hit something with great force
tatuchka [14]

Answer:

To strike or crash into with resounding impact. To collide or strike with great force. Used to indicate the sound of a forceful blow or collision.

8 0
3 years ago
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