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stich3 [128]
3 years ago
12

To strike or hit something with great force

Physics
2 answers:
tatuchka [14]3 years ago
8 0

Answer:

To strike or crash into with resounding impact. To collide or strike with great force. Used to indicate the sound of a forceful blow or collision.

timama [110]3 years ago
6 0

Answer:

To strike or crash into with resounding impact. To collide or strike with great force. Used to indicate the sound of a forceful blow or collision.

Explanation:

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Discuss a main factor negatively affecting species around the world and what scientist are doing in order to combat those proble
stiks02 [169]
These are the common main factors negatively affecting species around the world:

• Invasive species. The overview of non-native species into an ecosystem can intimidate endemic wildlife, distress human health and upset economies. Scientist solution contain making systems to avoid introduction of invasive species in the first place effectively monitoring for new infestations and fast abolition anew noticed intruders. 

• Over-exploitation. Overhunting, overfishing and overharvesting give importantly to the damage of biodiversity which is killing of numerous species over the past several hundred years. The solution is conservation and constant consciousness neighboring over-exploitation mostly poaching and overfishing. 

• Climate change. Alterations in climate over our planet past have altered life on earth in the long run which ecosystems have originate and left and species regularly go nonexistent. The solution must be reducing carbon prints and promoting education.

• Deforestation and habitat loss. This is a direct cause of extinction and loss of biodiversity. The solution is recommending stronger scientific forest protection laws. 

• Lastly is the pollution. Acid rain which is normally initiated by the burning of fossil fuels can acidify smaller bodies of water and soil harmfully affecting the species that live there by altering breeding and nourishing habits. The solution must combat atmospheric and hydrologic pollution. 
3 0
4 years ago
Which is longer, 10 cm or .01 m?
motikmotik

Answer:

They´re the same.

Explanation:

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6 0
3 years ago
Two cellists, one seated directly behind the other in an orchestra, play the same note for the conductor who is directly in fron
sergij07 [2.7K]

Answer:

Please see below as the answer is self-explanatory.

Explanation:

  • In order to have a destructive interference, the path difference between the sources of the sound, must be equal to an odd multiple of the semi-wavelength, as follows:
  • ⇒ d = d₂ - d₁ = n*(λ/2)
  • The minimum posible value for this distance, is when n=1, as it can be seen here:
  • dmin = λ/2
  • In any traveling wave, there exists a fixed relationship between the wave speed, the frequency and the wavelength:
  • v = λ*f
  • Therefore, assuming that the speed of sound keeps constant, if the frequency is increased, in order to keep the right side of the expression above balanced, λ must be decreased.
  • As the smallest separation that produces destructive interference is directly proportional to the wavelength, this means that this separation will decrease if the cellists produced a note with a higher frequency.

7 0
3 years ago
How many wolves are in the Southeast US
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Approximately 100-120 wolves
7 0
4 years ago
Read 2 more answers
A uniform line charge extends from x = - 2.6 cm to x = + 2.6 cm and has a linear charge density of = 5.5 nC/m.(a) Find the total
Mashutka [201]

Answer with Explanation:

We are given that

x=-2.6 cm to x=2.6 cm

Linear charge density=\lambda=5.5nC/m=5.5\times 10^{-9} C/m

1nC=10^{-9} C

Length of wire=2.6-(-2.6)=2.6+2.6=5.2cm

Length of wire=\frac{5.2}{100}=0.052m

1 m=100 cm

We know that

a.Linear charge density=\frac{Q}{L}

Where Total charge =Q

Length=L

Total charge,Q=\lambda L

Using the formula

Total charge,Q=5.5\times 10^{-9}\times 0.052=2.86\times 10^{-10}C

b.y=4 cm=\frac{4}{100}=0.04m

1 m=100 cm

Electric field on the y-axis is given by

E=\frac{2\lambda}{4\pi\epsilon_0 y}(\frac{L}{\sqrt{4y^2+L^2}}

\frac{1}{4\pi\epsilon_0}=9\times 10^9 Nm^2/C^2

Using the formula

E=\frac{2\times 5.5\times 10^{-9}\times 9\times 10^9\times 0.052}{0.04\times \sqrt{4(0.04)^2+(0.052)^2}}

E=1348.8N/C

c.y=12 cm=\frac{12}{100}=0.12m

Using the formula

E=\frac{2\times 5.5\times 10^{-9}\times 9\times 10^9\times 0.052}{0.12\times \sqrt{4(0.12)^2+(0.052)^2}}

E=174.7N/C

3 0
4 years ago
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