3 years ago

The work done to lift a 10kg object to a height of 1m above the ground is

Physics

1 answer:

vlada-n [284]3 years ago

8 0

A = mg∆h = 10•10•1 = 100J

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If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the

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$\Delta U = Q - W\\Q = mC \Delta T\\Q = mL$

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$Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J$

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We use this energy to convert steam into vapors.

$Q = \Delta E$

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