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qwelly [4]
1 year ago
5

How do you compare the energies of the different parts of the electromagnetic spectrum?

Physics
1 answer:
faltersainse [42]1 year ago
5 0

The different types of radiation in electromagnetic spectrum are compared by the amount of energy found in the photons.

Radio waves have photons with low energies, microwave photons have a little more energy than radio-waves. Infrared photons still have more energy, then comes visible, ultraviolet, x-rays and the most energetic of all, gamma rays.

The energy associated with electromagnetic radiation is proportional to frequency and inversely proportional to wavelength. So, electromagnetic waves with shorter wavelengths have more energy.

On one end of the electromagnetic spectrum are radio waves, which have wavelengths billions of times longer than those of visible light. On the other end of the spectrum are gamma rays with wavelengths billions of times smaller than those of visible light.

To know more about electromagnetic spectrum:

brainly.com/question/27839167

#SPJ4

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Workshop:The analysis of a simple pendulum assumed that the mass was a particle, with no size. A realistic pendulum is a small,
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3 years ago
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