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igomit [66]
3 years ago
7

Can someone help? it will end soon

Mathematics
1 answer:
inna [77]3 years ago
6 0

There are 2 of each angles

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On​ Monday, a museum had 400 visitors. On​ Tuesday, it had 780 visitors. Estimate the percent change in the number of visitors t
11Alexandr11 [23.1K]

Alright, lets get started.

Numbers of visitors on Monday = 400

Numbers of visitors on Tuesday = 780

So, percentage change = \frac{780-400}{400}*100

So, percentage change  = \frac{380}{400} *100

So, percentage change = 95 %    :    Answer

If same estimated percentage increase on next day also, means on Wednesday, the number of visitor will be = 780+ 780*95%

So,number of visitors on Wednesday = 780 + 741

Number of visitors on Wednesday = 1521     :    Answer


4 0
4 years ago
7. If 40% of a given number is 8, then what is 15% of the
Digiron [165]

Answer:

it is C

Step-by-step explanation:

40% of 20 is 8

so 15% of 20 is 3

7 0
4 years ago
Read 2 more answers
Which expression is equivalent to 2^2×2/2^4
dusya [7]
First step is to simplify the equation so that it makes our life easier! Since 2^2 is equivalent to 4, we can plug that into the equation. Then we can also simplify 2^4 to 16. Now it should look like this:

(4)(2)/16

Now we can solve. 4(2) = 8 so now we have 8/16. 8/16 simplifies to 1/8 when you divide the numerator and the denominator by 8. So there you go! Your final answer is 1/8! I really hope that helped you out, and happy holidays!
6 0
3 years ago
-4x - 6 = -5y + 9 y=
xxMikexx [17]

Answer:

y =4/5x + 3

Step-by-step explanation:

−4x−6=−5y+9

Step 1: Flip the equation.

−5y+9=−4x−6

Step 2: Add -9 to both sides.

−5y+9+−9=−4x−6+−9

−5y=−4x−15

Step 3: Divide both sides by -5.

−5y/−5

=

−4x−15/−5

y=

4/5x+3

Answer:

y=

4/5x+3

5 0
4 years ago
Read 2 more answers
Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.​
Galina-37 [17]

Question:

Prove that:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Answer:

Proved

Step-by-step explanation:

Given

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Required

Prove

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Subtract tan(10) from both sides

- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

Factorize the right hand size

tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)

Rewrite as:

tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))

Divide both sides by 1-tan(70). tan(100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)

In trigonometry:

tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}

So:

\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)} can be expressed as: tan(70 + 100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10) gives

tan(70 + 100) = -tan(10)

tan(170) = -tan(10)

In trigonometry:

tan(180 - \theta) = -tan(\theta)

So:

tan(180 - 10) = -tan(10)

Because RHS = LHS

Then:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) has been proven

6 0
3 years ago
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