There are many ways to find this answer. Perhaps the simplest is to realize how acceleration relates to velocity.
a=(vf-vi)/(t2-t1)
Now for this problem we know that the ball reaches its maximum height when v=0, because this is the point when velocity is changing from positive to negative, hence it is at its highest position. And we also know that the acceleration is only cause by gravity or about -32 ft/s^2.
So in general we know that a=g=-32, vf=0, vi=64, t1=0 and t2 is the time when the ball is at its maximum height so:
a=(vf-vi)/(t2-t1) becomes
g=-vi/t2
t2=-vi/g
t=-vi/g, and in this case
t=-64/-32
t=2 seconds
In general for any quadratic of the form ax^2+bx+c=y, the x-coordinate of the vertex, which is the point of either an absolute minimum or maximum for the quadratic:
x=-b/(2a)
Which again we can see in this case is:
t=-64/(2*-16)
t=-64/-32
t=2 seconds
75%off.. she paid 4$ for the scarf. if 16 = 100% (divided by 4 is 25% ) 4×3= 12 which equals 75 %. im sorry for the lengthy explanation im sure there is an easier way to explain i hope u understand the point i was getting at. it is definitely 75% off though
They want you to find the composite function and they evaluate it at a give value for x...first the composite function...
f(g(x))=(x-1.5)^2+3(x-1.5)+6
f(g(x))=x^2-3x+2.25+3x-4.5+6
f(g(x))=x^2+3.75, this is the completed composition function...now:
f(g(1)=1+3.75=4.75