<img src="https://tex.z-dn.net/?f=2%20%5Cdiv%203%20%2B%202%20-%206%20%5Cdiv%205%20-%202%20-%202%20%5Ctimes%203%20%5Cdiv%206%20-%

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3 years ago

204%20%2B%2035%20%5Ctimes%205%20%5Ctimes%205%20%2B%205" id="TexFormula1" title="2 \div 3 + 2 - 6 \div 5 - 2 - 2 \times 3 \div 6 - 4 + 35 \times 5 \times 5 + 5" alt="2 \div 3 + 2 - 6 \div 5 - 2 - 2 \times 3 \div 6 - 4 + 35 \times 5 \times 5 + 5" align="absmiddle" class="latex-formula">
what does it equal?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

4 0

I think its 721.6666667

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Below are the jersey numbers of 11 players randomly selected from a football team. Find the range, variance, and standard devia

padilas [110]

Answer:

Option(A) is correct

Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:

Highest = 97

Lowest = 71

Range = highest value - Minimum value

Range = 97 - 26 = 71

$Range= 71$

mean of the data is the summation of all the numbers in the data set divided by the number of given samples.

Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11

= 647/11

$Mean value =58.7$

Now to find the variance of the data set by using below formular

σ²=[ (xᵢ -mean)²]/n-1

[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10

$Variance=546$

Now, we will calculate standard deviation by taking square root over variance

σ =√(variance)

σ =√(546)

$Standard deviation= 23.4$

Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,

Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

5 0

3 years ago

Historically, the average time to service a customer complaint has been 3 days and the standard deviation has been 0.50 day. Man

kicyunya [14]

Oof I didn’t learn about this you can ask a class and go over it

6 0

3 years ago

Solve the problem by entering and solving an equation.

geniusboy [140]

Given : A rectangular picture frame has a perimeter of 52 inches. The height of the frame is 12 inches.

To Find : The width of the frame .

Solution : Let us take the width of the frame be x . So , we know the formula to find the perimeter of rectangle as ;

$\boxed{\red{\bf Perimeter_{rectangle}=2(l+b)}}$

Where , l is the length of the rectangle and b is the breadth of the rectangle .

⇒ Perimeter = 2 ( l + b ) .

⇒ 52 in. = 2 ( 12 + x ) in.

⇒ 52 in.= 24in. + 2x .

⇒ 2x =( 52 - 24 ) in

⇒ 2x = 28 in.

⇒ x = 28/2 in.

⇒ x = 14 in.

Hence the width of the rectangle is 14 inches.

5 0

3 years ago

A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ (Approximated)

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ (Approximated)

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3 years ago

What is the probility of tossing talls twice

Rom4ik [11]

Hdhdiduwhshuxjfjdksoosoxod

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3 years ago