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ASHA 777 [7]
3 years ago
13

What is the length of DE A. 7 B. 6 C. 5 D. 8

Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:6

Step-by-step explanation: Since the angles are the same, the sides will be proportionate in each triangle.  

12/8 = 1.5 so 9/x = 1.5.

x=6

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In 2009, a school population was 1,700. By 2017 the population had grown to 2,500. Assume the population is changing linearly. W
qaws [65]

Answer:

100

Step-by-step explanation:

The population is changing linearly. This means that the population is increasing by a particular value n every year.

From 2009 to 2017, there are 8 increases and so, the population increases by 8n.

The population increased from 1700 to 2500. Therefore, the population increase is:

2500 - 1700 = 800

This implies that:

8n = 800

=> n = 800/8 = 100

The average population growth per year is 100.

4 0
4 years ago
200/160 as a percentage (200 over 160)
dem82 [27]

Answer:

80%

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Determine if the statement is always, sometimes or never true. There are 250 degrees in the sum of the interior angles of a poly
stiv31 [10]
I feel like the answer is sometimes
5 0
3 years ago
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

Now, the probability of both black and red card = $ \frac{1}{2} \times \frac{26}{51} $

$ = \frac{\textbf{13}}{\textbf{51}} $

Hence, the answer.

5 0
4 years ago
3 cards are chosen at random from a standard 52-card deck. what is the probability that they form a pair? (a 3-card hand is a 'p
kozerog [31]

Hello!

First of all, we have a 4/52, or 1/13 chance of selecting a pair. Then, we select 1/3 cards 3 times, so we use this as our other fraction.

\frac{1}{13}\cdot \frac{1}{3}=\frac{1}{39}

Therefore, we have a 1/39 or about 3%.

I hope this helps!

8 0
3 years ago
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