Question

Find The Value Of x ?

Answer 1

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Question 1 :

$\qquad \sf \dashrightarrow \: log_{ {3} }( \frac{1}{3} ) = x$

$\qquad \sf \dashrightarrow \: log_{ {3} }( {3}^{ - 1} ) = x$

$\qquad \sf \dashrightarrow \: log_{ {3} }( {3})^{ - 1 } = x$

$\qquad \sf \dashrightarrow \: - 1 \times log_{3}(3) = x$

$\qquad \sf \dashrightarrow \: - 1 \times 1 = x$

$\qquad \sf \dashrightarrow \: x = - 1$

Question 2 :

$\qquad \sf \dashrightarrow \: log_{3}(x - 1) = 2$

$\qquad \sf \dashrightarrow \: x - 1 = {3}^{2}$

$\qquad \sf \dashrightarrow \: x = 9 + 1$

$\qquad \sf \dashrightarrow \: x = 10$

Answer 2

Answer:

1) $x = -1$  ||     2) $x = 10$

Explanation:

1)

→ $\log _3\left(\frac{1}{3}\right)=x$

→ $\frac{1}{3} = 3^x$

→ $3^{-1} = 3^x$

→ $x = -1$

2)

→ $\log _3\left(x-1\right)=2$

→ $x - 1 = 3^2$

→ $x -1 = 9$

→ $x = 9 +1$

→ $x = 10$