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2 years ago

How do deep currents form ???

Chemistry

1 answer:

Fofino [41]2 years ago

3 0

Answer:

The sinking of large masses of cool water gives rise to the (aka thermohaline circulation), which is derived by density gradients due to variations in the temperature and the salinity. The earth's rotation on its axis also influences deep ocean currents (the high and low tides).

Explanation:

Salinity is the saltiness or amount of salt dissolved in a body of water, called saline water- Dictionary term

Density is the degree of compactness of a substance.- Dictionary term

Hope that helps

You might be interested in

Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate t

sukhopar [10]

To find the mass you divide multiply volume and density..

Density = 1.79 x 10^-4 Volume = 6.3

(1.79 x 10^-4 )(6.3) = 1.1 x 10^-3 g

7 0

2 years ago

Read 2 more answers

Which material is the least likely to be recognized as a mixture by looking at it under a microscope

PSYCHO15rus [73]

A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water!

5 0

3 years ago

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How much energy is needed to raise the temperature of 125g of water from 25.0oC to 35.0oC? The specific heat of water is 4.184

Anvisha [2.4K]

Hello!

To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.

In this formula, q is the heat absorbed, m is the mass, c is the specific heat, and Δt is the change in temperature, which is found by final temperature minus the initial temperature.

Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.

35.0° C - 25.0° C = 10.0° C

We are also given the specific heat and the grams of water. With that, we can substitute the given values into the equation and multiply.

q = 125 g × 4.184 J/g °C × 10.0° C

q = 523 J/°C × 10.0° C

q = 5230 J

Therefore, it will take 5230 joules (J) to raise the temperature of the water.

6 0

3 years ago

7. Suppose 1.01 g of iron (III) chloride is placed in a 10.00-mL volumetric flask with a bit of water in it. The flask is shaken

Nana76 [90]

Answer: The molarity of Iron (III) chloride is 0.622 M.

Explanation:

Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of iron (III) chloride = 1.01 g

Molar mass of iron (III) chloride = 162.2 g/mol

Volume of the solution = 10 mL

Putting values in above equation, we get:

$\text{Molarity of Iron (III) chloride}=\frac{1.01g\times 1000}{162.2g/mol\times 10mL}\\\\\text{Molarity of Iron (III) chloride}=0.622M$

Hence, the molarity of Iron (III) chloride is 0.622 M.

3 0

2 years ago

Calculate the mass of each element in the

Lelechka [254]

Answer:

For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively

Explanation:

The computation of the mass of each element is given below:

As we know that

A1 mole of ammonium nitrate i.e. 2 mol N, 4 mol H, 3 mol

Now we multiply each of above by the molar masses

For N

= 14.0 g/mol × 2

= 28.0 gN

For H

= 1.0 g/mol × 4

= 4.0 gN

ANd, for O

= 16.0 g/mol × 3

= 48.0 gN

Hence, For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively

7 0

2 years ago