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2 years ago

15

Two springs with spring constants k1 and k2 are connected together. With mass m1 attached, the springs have

1 answer:

Monica [59]2 years ago

7 0

K1x1=k2x2=F
k2x2/k1=x1
F=keqx=keq(x1+x2)

sub.s in for x1:F=keq(k2x2/k1+x2)

sub.s in for F (in terms of k2 and x2)k2x2=keq(k2x2/k1+x2)

x2 is in every term:k2=keq(k2/k1+1)

multiply both sides by (k1/k2+k1)
keq=(k1/k1+k2)k2
keq=(1/k1+1/k2)−1

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According to Hund's rule of maximum spin multiplicity, how many singly-occupied orbitals are there in the valence shells of the

leva [86]

Answer:

A) carbon - 2

B) cobalt - 3

C) sulfur - 2

D) fluorine - 1

E) titanium - 2

F) germanium - 2

Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.

(A) Carbon.

The electronic configuration is -

$1s^22s^22p^2$

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

(B) Cobalt.

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{7}4s^2$

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -

$1s^22s^22p^63s^23p^4$

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

D) fluorine

The electronic configuration is -

$1s^22s^22p^5$

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

E) Titanium

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{2}4s^2$

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{10}4s^24p^2$

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

4 0

3 years ago

Salts are which part of an aqueous solution?

masha68 [24]

Explanation:

Salts are the solutes in an aqueous solution. An aqueous solution is solution whose solvent water.

To form a solution,a solute must be dissolved in a solvent.
For aqueous solutions, the solvent which is the dissolving medium is made up of water.
The solute is the substance that is dissolved in it.
Salts for example can be a solute in an aqueous solution.
A salt is generally an ionic compound consisting of positive ions such as metallic, ammonium ans complex ions and negative ions such as acid radicals and complex ions.

Learn more:

Aqueous solution brainly.com/question/8426727

#learnwithBrainly

3 0

2 years ago

Assuming that the experiments performed in the absence of inhibitors were conducted by adding 5 μl of a 2 mg/ml enzyme stock sol

prohojiy [21]

Hey there!:

From the given data ;

Reaction volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )

Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:

[E]t in molar = g/L * mol/g

[E]t = 0.01 g/L * 1 / 45,000

[E]t = 2.22*10⁻⁷

Vmax = 0.758 umole/min/ per mL

= 758 mmole/L/min

=758000 mole/L/min => 758000 M

Therefore :

Kcat = Vmax/ [E]t

Kcat = 758000 / 2.2*10⁻⁷ M

Kcat = 3.41441 *10¹² / min

Kcat = 3.41441*10¹² / 60 per sec

Kcat = 5.7*10¹⁰ s⁻¹

Hence kcat of xyzase is 5.7*10¹⁰ s⁻¹

Hope that helps!

4 0

3 years ago

An adult mosquitoes lifespan is about 16 days how many minutes is that

Delicious77 [7]

1 day = 1, 440 minutes
16 days = (1, 440 × 16) days = 23, 040 minutes

5 0

3 years ago

The picture below shows the positions of the Earth, Moon, and Sun during an eclipse.

SVETLANKA909090 [29]

Answer:

it is option c liner eclipse

7 0

2 years ago

Read 2 more answers