Answer:
The partial pressure of water is much less than 1atm, so the free energy change for the process must be negative with ΔGrxn<0.
Explanation:
Water vapor will condense into liquid water when the water vapor is in its standard state, with a pressure of 1atm. Under normal circumstances, the partial pressure of water vapor is much less that 1atm. It is in a nonstandard state. The free energy change of this reaction has to be negative in order to make the reaction spontaneous.
For precipitation to happen, first tiny water droplets must condense on even tinier dust, salt, or smoke particles, which act as a nucleus. Water droplets may grow as a result of additional condensation of water vapor when the particles collide. If enough collisions occur to produce a droplet with a fall velocity which exceeds the cloud updraft speed, then it will fall out of the cloud as precipitation.
Answer:
The answer is the same as 9.11x10-31kg which is the mass of an electron,
Explanation:
The mass of an electron expressed in standard form is 9.11x10-31, which is the same thing as 0.000000000000000000000000000000911, while the former looks compact and easier to understand, the latter is clumsy,
The concept of three significant figures mean, three non-zero figures, in other words, provide your answer in an approximate form using three figures apart from zero, so you would try to express your answer in such a way that the first digit in your answer is not zero, in this case, its a "nine" - "9", and the other two significant figures are "1" and "1".
Answer:
$182 is the value of the gold in the coin
Explanation:
Diameter is 2r, the ratio of the coin is = 1.62cm / 2 = 0.81cm
Following the formula of the volume of the coin:
V = π r² h
V = π*(0.81cm)²*0.085cm
V = 0.172cm³ = mL
As the density of the gold is 19.32g/mL, the mass of 0.1752mL of gold is:
0.1752mL * (19.32g / mL) =
3.385g is the mass of the coin
As the price of the gold is $53.90 / g, the value of the gold in the coin is:
3.385g * ($53.90 / g) =
<h3>$182 is the value of the gold in the coin</h3>
