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1 year ago

Mass of 12.04 ×10²³ atoms of Mg is .........

Chemistry

1 answer:

yarga [219]1 year ago

6 0

What is in my calculator should be the answer u might have to round to the nearest tenths place

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Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li(s) + N2(g) → 2Li3N(s) How many moles of lit

miss Akunina [59]

Answer:

12.5 g of Li are needed in order toproduce 0.60 moles of Li₃N

Explanation:

The reaction is:

6Li(s) + N₂(g) → 2Li₃N(s)

If nitrogen is in excess, the lithium is the limiting reactant.

Ratio is 2:6

2 moles of nitride were produced by 6 moles of Li

Then, 0.6 moles of nitride were produced by (0.6 .6)/ 2 = 1.8 moles of Li

Let's convert the moles to mass → 1.8 mol . 6.94 g/ 1mol = 12.5 g of Li

7 0

3 years ago

Read 2 more answers

Write a balanced chemical equation for the reaction between ammonium

Natasha2012 [34]

Answer:

(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)

Explanation:

Data Give:

Reaction between ammonium phosphate solution and solution of aluminum nitrate

Write a balanced chemical equation

include phase symbols

Details:

To write a balanced chemical equation we have to know formula units of compounds or molecules

Formula units

ammonium phosphate : (NH₄)₃PO₄

aluminum nitrate: Al(NO₃)₃

ammonium nitrate: NH₄NO₃

Now to write a chemical equation

we have to write the chemical formulas or formula unit of each compound
write the reactant on left side of the arrow
write the product on the right side of the arrow
put a plus sign in 2 reactants and products on each side of the arrow
balance the equation by putting coefficient with compound formula
write the phase symbols on the right corner of the compound formula in brackets

So the Reaction will be

(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + NH₄NO₃

Now balance the Chemical equation

(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + 3NH₄NO₃

Now write the phase Symbols

(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)

all compounds in the reaction are in liquid form and soluble in water

*** Note:

There is no aluminum nitrite in chemicals formulas

Also ammonium nitrite can not be used in pure isolated form due to its highly instability

4 0

3 years ago

What begins to happen to radioactive uranium as soon as a mineral containing it crystallizes from magma?

Aleonysh [2.5K]

The radioactive uranium decays into its daughter product, lead. It would do this in magma as well, as nuclear decay depends on forces within the atom, not on the phase of the material in which the atom is a part.

5 0

3 years ago

What is the volume of 120 mg of water? A. 1.2 dL B. 120 mL C. 120 L D. 1.2 L

mojhsa [17]

I would say B but I am not sure so sorry if it is wrong!!

3 0

3 years ago

In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z

storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

Step 1: Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0

3 years ago