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slega [8]
2 years ago
6

HELPPPPPPP MEEEE PLEASE

Mathematics
2 answers:
marissa [1.9K]2 years ago
5 0
Answer:
1/2

Solution: plugging in the given information into the formula you get 2/4 which simplifies to 1/2
Keith_Richards [23]2 years ago
4 0

\huge\underbrace{\tt\pink{Answer}}

Given equation :

⟹\:\frac{{x}^{2}\:-\:\sqrt[3]{4y}}{|xy|} \\

x\:=\:-2\:\:\:\:\:\:\:\:y\:=\:2

we have to evaluate .

⟾ \:\frac{{(-\:2)}^{2}\:-\:\sqrt[3]{4(2)}}{|-\:2(2)|} \\

⟾ \:\frac{4\:-\:\sqrt[3]{8}}{|-4|} \\

⟾ \:\frac{4\:-\:2}{4} \\

⟾ \:\frac{2}{4} \\

⟾ \:{\cancel\frac{2}{4}} \\

⟾ \:\frac{1}{2}\\

{\large{\color{cyan}{\boxed{AnS\:→\:\frac{1}{2}}}}}

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The answer please for my online class
Eddi Din [679]

Answer:

B. -500

Step-by-step explanation:

\dfrac{(2a^4)^2}{a^0a^5} =

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3 years ago
How do I do this? <br><br> -2(6-r)=4
Tcecarenko [31]

Answer:r=8

Step-by-step explanation:

5 0
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What is the slope of the line represented by<br><br> y= 12+ 1/2x ?
trasher [3.6K]

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1/2

Step-by-step explanation:

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2 years ago
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bonufazy [111]

9514 1404 393

Answer:

  (-4√494)/13i +(6√494)/13k ≈ -6.8388i +0j +10.2585k

Step-by-step explanation:

To answer this question, you need to know two things:

  1) the direction of vector v

  2) the magnitude of vector u

__

<u>direction of v</u>

A direction is specified by a "unit vector", one with the proper ratio of components, and a magnitude of 1. It is found from a given vector by dividing that vector by its magnitude.

The unit vector in the v direction is ...

  v/|v| = (-2i +3k)/(√((-2)² +3²) = (-2i +3k)/√13

__

<u>magnitude of u</u>

The magnitude of vector u is ...

  |u| = √(5² +(-2)² +3²) = √38

__

Then the desired vector is ...

  (2|u|)(v/|v|) = 2√38(-2i+3k)/√13 = (-4√494)/13i +(6√494)/13k

_____

<em>Additional comment</em>

We have chosen to "rationalize the denominator" by writing √(38/13) as (√494)/13.

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3 years ago
Will give branliest pls help!
riadik2000 [5.3K]

Answer:

Step-by-step explanation:

   

3 0
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