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2 years ago

WILL GIVE BRAINLIEST PLEASE ANSWER ALL QUESTIONS

Physics

1 answer:

Rainbow [258]2 years ago

5 0

There would be more - charges on the peanuts because they gain electrons which are represented with the - sign. There would also be more + on the cat to show that the cat’s fur is positively charged. The peanuts would be attracted to the cat because opposite charges attract.

As for explaining the first model, there should be the same amount of + and - charges on the peanuts as well as the cat to show that it is balanced and the peanuts are not attracted or repelled by the cat.

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A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50

PSYCHO15rus [73]

Answer:

(a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

Explanation:

Given that,

Length = 50.00 cm

Time period = 2.50 s

Time period of pendulum is defined as the time for one complete cycle.

The period depends on the length of the pendulum.

Using formula of time period

$T=2\pi\sqrt{\dfrac{I}{mgh}}$

Where, I = moment of inertia

We need to calculate the value of d

Using parallel theorem of moment of inertia

$I=I_{cm}+md^2$

For a meter stick mass m , the rotational inertia about it's center of mass

$I_{cm}-\dfrac{mL^2}{12}$

Where, L = 1 m

Put the value into the formula of time period

$T=2\pi\sqrt{\dfrac{\dfrac{mL^2}{12}+md^2}{mgd}}$

$T=2\pi\sqrt{\dfrac{L^2}{12gd}+\dfrac{d}{g}}$

$T^2=4\pi^2(\dfrac{L^2}{12gd}+\dfrac{d}{g})$

Multiplying both sides by d

tex]T^2d=4\pi^2(\dfrac{L^2}{12g}+\dfrac{d^2}{g})[/tex]

$(\dfrac{4\pi^2}{g})d^2-T^2d+\dfrac{\pi^2L^2}{3g}=0$

Put the value of T, L and g into the formula

$4.028d^2-6.25d+0.336=0$

$d = 0.056\ m, 1.496\ m$

The value of d is 0.056 cm and 1.496 cm.

(b). Given that,

L = 50-5 = 45 cm

We need to calculate the time period

Using formula of period

$T=2\pi\sqrt{\dfrac{l}{g}}$

Put the value into the formula

$T=2\pi\sqrt{\dfrac{45\times10^{-2}}{9.8}}$

$T=1.35\ sec$

Hence, (a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

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3 years ago

The transfer of energy in liquids and gases as groups of molecules move in currents is

AlexFokin [52]

Convection is your answer

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3 years ago

Superman is riding his bicycle. At the base of a hill, he has a specific amount of kinetic energy. Then he coasts up the hill wi

algol13

Answer:

D. Friction and air resistance created heat on his trip up the hill.

Explanation:

Energy transformation from one form to another is not 100% efficient. This is the postulate of the first law of thermodynamics.

Most of the energy transformation is not purely 100%.

When energy is transformed, some are usually wasted.

In this case, in moving from bottom up, Superman produced some heat and encountered air resistance.
To reach the top, he must have overcome the resistance and produce enough heat to power him through.
This reduces the amount of potential energy that should have been the same as the kinetic energy down below.

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3 years ago

(a) Calculate the magnitude of the gravitational force exerted on a 497-kg satellite that is a distance of 1.92 earth radii from

Setler [38]

Answer:

a) 1321.45 N

b) 1321.45 N

c) 2.66 m/s^2

d) 2.21*10^-22 m/s^2

Explanation:

Hello!

First of all, we need to remember the gravitational law:

$F = G \frac{m_1 m_2}{r^2}$

Were

G = 6.67428*10^-11 N(m/kg)^2

m1 and m2 are the masses of the objects

r is the distance between the objects.

In the present case

m1 = earth's mass = 5.9742*10^24 kg

m2 = 497 kg

r = 1.92 earth radii = 1.92 * (6378140 m) = 1.2246*10^7 m

Replacing all these values on the gravitational law, we get:

F = 1321.45 N

a) and b)

Both bodies will feel a force with the same magnitude 1321.45 N but directed in opposite directions.

The acceleration can be calculated dividing the force by the mass of the object

a_satellite = F/m_satellite = ( 1321.45 N)/(497 kg)

a_satellite = 2.66 m/s^2

a_earth = F/earth's mass = (1321.45 N)/( 5.9742*10^24 kg)

a_earth = 2.21*10^-22 m/s^2

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3 years ago

What negatively charged particle was discovered through the study of cathode rays?

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The particle discovered in cathode rays was the electron

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