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UNO [17]
4 years ago
10

Using a cathode ray tube, Thomson confirmed that

Physics
2 answers:
Natasha2012 [34]4 years ago
4 0
<span>atoms are made of particles that have a negative charge.</span>
Westkost [7]4 years ago
4 0

Option (B) is correct .i.e. atoms are made of particles that have negative charge.

Further explanation:

Using cathode ray tube, <u>J.J Thomson</u> found that something emits from the negative plate (called as cathode) and goes towards the positive plate (called as anode), and on applying zinc sulfide (also called phosphor) coating on the perforated anode, it shows green fluorescence at some particular values of pressure and temperature.

William Crookes called them the cathode rays as were originated from cathode. Further, Atoms are overall neutral having equal amounts of positive and negative charge as he explained in his plum pudding model.

Although, electrons in atoms have varying energy but this was not confirmed by J.J. Thomson, also electrons can’t be inside nucleus because this would make atoms very unstable.

Some of the properties of those cathode rays are as follows:

(1). They are made up of material particles (they made the light wheels rotate that come in their path).

(2). The green fluorescence was also observed when he putted two more plates perpendicular to the earlier path and the rays followed a curved path towards the new anode.

(3). They has an ionizing property (they ionizes the gas present in the cathode ray tube, through which they pass).

Thus, <u>Option (B) is correct because the cathode rays are emitted from the metallic plate which’s atoms have particles having negative charge.</u>

Learn More:

1. A radio station's channel, such as 100.7 fm or 92.3 fm, is actually brainly.com/question/9527365

2. A very long, uniformly charged cylinder has radius r and linear charge density λ brainly.com/question/1834208

3. The results of Rutherford's gold foil experiment demonstrated that brainly.com/question/1542931

Answer Details:

Grade: High School

Subject: Physics

Chapter: Modern physics

Keywords:

Atoms, cathode, cathode rays, cathode ray tubes, J.J. Thomson, negatively charged particles, nucleus, energy, varying energy, electrons, green fluorescence, phosphor, anode, protons, pressure, temperature, William Crookes.

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natita [175]
Middle school? lol but, the third one.
5 0
3 years ago
What is the meaning of the reference point in electric potential?.
mrs_skeptik [129]

Answer:

<h3><u>ELECTRIC POTENTIAL</u></h3>

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4 0
2 years ago
How many 1140 nm long molecules would you have to line up end to end to stretch a distance of 158 miles?
dezoksy [38]

Answer:

221754385964.9123

Explanation:

Convert miles to nanometer

1 mile = 1.6 km

1 km = 1×10³×10³×10³×10³ nm

1 mile = 1.6×10¹² nm

So,

158 miles = 158×1.6×10¹² = 252.8×10¹² nm

Length of each molecule = 1140 nm

Number of molecules = Total length / Length of each molecule

\text{Number of molecules}=\frac{252.8\times 10^{12}}{1140}\\\Rightarrow \text{Number of molecules}=221754385964.9123

There are 221754385964.9123 number of molecules in a stretch of 158 miles

3 0
4 years ago
Under what conditions would a rope remain in equilibrium during a tug of war?
Anettt [7]
The best and most correct answer among the choices provided by the question is the second choice. The rope will not be broken until the net force acting on it is not equal to zero anymore. I hope my answer has come to your help. God bless and have a nice day ahead!
5 0
4 years ago
Read 2 more answers
Find the minimum kinetic energy in MeV necessary for an α particle to touch a 39 19 K nucleus that is initially at rest, assumin
SIZIF [17.4K]

Answer:

KE = 9.6MeV

Explanation:

Given the relationships we understand that,

q_1 = 19e, q_2 = 2e

The Potential at point p, is given by the following formula

V_ {p} = \frac {Kq_1} {r}

According to the graphic designed, you have,

V_ {p} = \frac {Kq_1} {(r_1 + r_2)}

V_ {p} = \frac {(9 * 10 ^ 9) (19 * 1.6 * 10 ^ {- 15})} {(3.7 + 2) * 10 ^{- 15}}}

V_ {p} = 4.8 * 10 ^ 6V

The kinetic energy of the particle would be given by

KE = q_2 * V_ {p} = 2e * 4.8 * 10 ^ 6V

KE = 9.6MeV

4 0
3 years ago
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