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adoni [48]
2 years ago
12

A wall (of thermal conductivity 0.98 W/m · ◦ C) of a building has dimensions of 3.7 m by 15 m. The average inside and outside

temperatures are, respectively, 12â—¦C and 8â—¦C. If the heat transfer rate through the wall is 1540 W, what is the thickness of the wall in centimeters? Answer in units of cm. ________
Physics
1 answer:
disa [49]2 years ago
4 0

Answer:

Answer:

the amount of energy flowing is 1.008x10⁹J

Explanation:

To calculate how much heat flows, the expression is the following:

Where

K=thermal conductivity=0.81W/m°C

A=area=6.2*12=74.4m²

ΔT=30-8=22°C

L=thickness=8cm=0.08m

t=time=16.9h=60840s

Replacing:

Explanation:

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Heat from burning fuel warms the walls of the firebox section of the furnace in
nydimaria [60]

Heat from burning fuel warms the walls of the firebox section of the furnace in

A. a hot-water heating system.

B. a hot-air heating system.

C. a compressor compartment.

D. an evaporation system.

7 0
3 years ago
Each orbit is limited to a maximum of four electrons true or false
Naya [18.7K]
This question would be false
7 0
3 years ago
a water-balloon launcher with mass 4 kg fires a 0.5 kg balloon with a velocity of 3 m/s to the east. what is the recoil velocity
kotykmax [81]
I think we will use the law of conservation of linear momentum;
M1V1 = M2V2
M1 =  4 kg (mass of the water balloon launcher)
V1=?
M2= 0.5 kg ( mass of the balloon)
V2 = 3 m/s

Therefore; 4 V1 = 0.5 × 3
                   4V1= 1.5
                     V1= 1.5/4
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5 0
3 years ago
Read 2 more answers
Which observational tool helped astronomers Arno Penzias and Robert Wilson discover the
iren2701 [21]

Answer:

A radio telescope helped the astronomers discover the CMB.

Explanation:

  • Penzias and Wilson while experimenting with a radio telescope in 1964, accidentally discovered the radiation that exists universally also known as the CMB.
  • This was used to support the "Big Bang Theory" and not the "Steady State Theory"
  • CMB is the faint cosmic radiation that fills up the universe. It provides important data for understanding early universe.
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3 0
3 years ago
A
ale4655 [162]

m = 43.2 kg

Explanation:

volume of sphere = (4/3)pi(r)^3

= (4/3)(3.14)(2 m)^3

= 33.5 m^3

density = mass/volume

or solving for mass m,

m = (density)×(volume)

= (1.29 kg/m^3)(33.5 m^3)

= 43.2 kg

3 0
3 years ago
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