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natali 33 [55]
2 years ago
11

Code a program that gets all possible solutions of a string using 3 for loops. Actual question attached

Computers and Technology
1 answer:
Nikitich [7]2 years ago
8 0

\tt x=int(input("Enter\:first\:no:"))

\tt y=int(input("Enter\:second\:no:"))

\tt z=int(input("Enter\:third\:no:"))

\tt for\:x\:in\: range (3):

\quad\tt for\:y\:in\:range(3):

\quad\quad\tt for\:z\:in\:range(3):

\quad\quad\quad\tt if\:x!=y\:and\:y!=z\:and\:z!=x:

\quad\quad\quad\quad\tt print(x,y,z)

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Answer:

1. G=D+(A+C^2)*E/(D+B)^3

cobegin:

p1: (D+B)

p2: p1^3

p3: C^2

p4: A+ p3

p5: E/p2

p6: p4 * p5

p7: D + p6

   :G

coend

2. Now The value A=2, B=4, C=5, D=6, and E=8

p1: 6+4 =10

p2: p1 ^3= 10^3= 1000

p3: c^2= 5^2 =25

p4: A + p3= 2 +25 =27

p5: 8/1000

p6: 27 *8/1000

p7: D+ P6= 6+ 216/1000

      = 6216/1000

      =6.216

Explanation:

The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.

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3 years ago
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Class b and c networks cannot be sub netted.
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A doorknob is an example of a:
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