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tresset_1 [31]
2 years ago
5

Yooo im from k12 please help me rqqq!!!

Mathematics
2 answers:
Vikentia [17]2 years ago
8 0

\\ \tt\hookrightarrow 12x^4(-56x^3y^2)

\\ \tt\hookrightarrow -672x^{4+3}y^2

\\ \tt\hookrightarrow -672x^7y^2

None of the above

jek_recluse [69]2 years ago
3 0

\sf \: 12x^{4} ( - 56x^{3}  {y}^{2} )

Multiplying a positive and a negative equals a negative: (+)×(-)=(-)

\sf \:  { - 12x}^{4}  \times 56 {x}^{3}  {y}^{2}

Calculate the product

\boxed{ \tt - 672x^{7}  {y}^{2} }

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Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.
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1 year ago
1. Six units to the left of 3
trapecia [35]

Answer:

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8 0
2 years ago
Write the first 6 terms of the arithmetic sequence whose first term is 8 and has a common difference of 2
soldier1979 [14.2K]

Answer: The first 6 terms are = 8, 10, 12,14,16,18

Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

where a1 = First term  given as 8 and

d=  common difference given as 2

Therefore  We have that

the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

a1= 8

second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

= 8+ 2(1) = 10

3rd term

an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2

= 8+ 2(2)= 8 + 4=12

4th term

an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2

= 8+ 2(3)= 8+6=14

5th term

an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2

= 8+ 2(4)=8+ 8=16

6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

= 8+ 2(5)=8 +10 =18

6 0
2 years ago
Write the equation for the function graphed below.
avanturin [10]
Given the vertex of the parabola at point (2, -3):

The quadratic function in vertex form is:

f(x) = (x - 2)^2 - 3

where the vertex (h, k) is the minimum point = (2, -3).
6 0
2 years ago
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