Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a
b
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
Answer:
7.5^2
56.25
Step-by-step explanation:
I would say your answer is false because my mom works on houses and she never does this....
Hope I Helped (:
lets draw a picture of our hexagon:
then, we can rotate 60 degrees counterclockwise (or clockwise) and get the same hexagon. So, the answer is 60 degrees
(24, 12) and (36, 0). The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0. These two points satisfy both conditions and both sum to 36.