Answer:
The position of the first dark spot on the positive side of the central maximum is 1.26 mm.
Explanation:
Given that,
Wavelength of light is 633 nm.
Slit width, d = 0.5 mm
The diffraction pattern forms on a screen 1 m away from the slit. We need to find the position of the first dark spot on the positive side of the central maximum.
For destructive interference :
Y is the distance of the minima from central maximum
Here, n = 1
So, the position of the first dark spot on the positive side of the central maximum is 1.26 mm.
Answer:
Therefore,
The frequency heard by the engineer on train 1
Explanation:
Given:
Two trains on separate tracks move toward each other
For Train 1 Velocity of the observer,
For Train 2 Velocity of the Source,
Frequency of Source,
To Find:
Frequency of Observer,
(frequency heard by the engineer on train 1)
Solution:
Here we can use the Doppler effect equation to calculate both the velocity of the source 
and observer 
, the original frequency of the sound waves 
and the observed frequency of the sound waves 
,
The Equation is
Where,
v = velocity of sound in air = 343 m/s
Substituting the values we get
Therefore,
The frequency heard by the engineer on train 1
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> = initial velocity, <em>v</em> = final velocity, <em>a</em> = acceleration, and ∆<em>x</em> = distance traveled.
So
<em>v</em>² - (15 m/s)² = 2 (6.5 m/s²) (340 m)
<em>v</em>² = 4645 m²/s²
<em>v</em> ≈ 68.15 m/s
Answer:36.4 ft
Explanation:
Given
Span of Parabola 
Maximum height 
suppose Parabola is of type
where 
is the center of parabola
at 
and it is given, 
thus
at 
