Answer:
Explanation:
Net torque is calculated by multiplying the force with distance from the point of application of force to the point of pivot .
If more than 2 forces are present, then we either subtract the product of forces with their respective distances from pivot point or we add them . It depends on whether they both are present on opposite sides of pivot or on same side of pivot .
When a force is applied directly to the pivot point of balance, then the torque on due that force = 0 (zero) .
It is so because the torque is defined as the product of force and perpendicular distance from the pivot point but here the distance is 0 , therefore torque is zero.
Answer:
The boy has a greater momentum
Explanation:
The reason why the boy has a greater momentum is because the truck is at rest so it isn’t moving and momentum has to do with the quantity of motion
Answer:
159 N
Explanation:
The force of friction, Fr is a product of coefficient of feiction and the normal force. Therefore, Fr=uN where N is the normal force and u is coefficient of friction. Here, we have two coefficients of friction but since it is sliding, then we use coefficient of kinetic energy. Substituting 0.25 for u and 636 N for N then
Fr=0.25*636=159 N
Therefore, the force of friction is equivalent to 159 N
Answers:
Power - Measure of energy delivered by the circuit per unit time
Transistor - Can be used as a switch or amplifier
Voltage - A measure of the electrical potential difference across or between two points
Ohm’s Law - For a given voltage, current and resistance are inversely proportional
We need first to use the formula F=m(a+g), m iis the total mass, a is the acceleration, g is gravity pulling the blocks. So the procedure will be
<span>m=2kg(both blocks)+500g(both ropes) → m=2.5kg </span>
<span>a=3.00m/s^2 </span>
<span>g=9.8m/s^2 </span>
<span>F=m(a+g) → F=2.5kg (3.00m/s^2 + 9.8m/s^2) → F=2.5kg (12.8m/s^2) → F=32 N
To calculate the tension at the top of rope 1 you need to use the formula </span>T=m(a+g) so it will be <span>T=m(a+g) → T=1.5kg(12.8m/s^2) → T=19.2N
</span>We can now calculate the tension at the bottom of rope 1 using the formula: <span>T=m(a+g) → T=1.25kg(12.8m/s^2) → T=16N
</span>Now to find the tension at the top of rope 2 we do it like this:
<span>T=m(a+g) → T=.25kg(12.8m/s^2) → T=3.2</span>
