Answer:
1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.
Explanation:
The acceleration of an object in a circular path is
![a = \frac{v^2}{r}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv%5E2%7D%7Br%7D)
As can be seen from the equation, if the radius of the circle is decreases, the magnitude of the acceleration increases.
As for the direction of the acceleration, it is always towards the center, and it is always perpendicular to the direction of the velocity.
Answer:
volume is the correct answer
Explanation:
Answer:
230 m/s northeast, 1.8 m/s up
Explanation:
204 kilometres = 204000 metres
15.0 minutes = 900 seconds
Velocity = Distance / Time
= 204000 / 900
= 230 m/s northeast (to 2 sf.)
1.6km = 1600 metres
Velocity = 1600 / 900
= 1.8 m/s up (to 2 sf.)
Read more on Brainly.com - brainly.com/question/13863590#readmore
Answer:
-414.96 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
![v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20a%3D%5Cfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B0%5E2-3.85%5E2%7D%7B2%5Ctimes%200.75%7D%5C%5C%5CRightarrow%20a%3D-9.88%5C%20m%2Fs%5E2)
![F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N](https://tex.z-dn.net/?f=F%3Dma%5C%5C%5CRightarrow%20F%3D42%5Ctimes%20-9.88%5C%5C%5CRightarrow%20F%3D-414.96%5C%20N)
The force the ground exerts on the parachutist is -414.96 N
If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase
In mechanics, the normal force<span> is the component, perpendicular to the surface (surface being a plane) of contact, of the contact </span>force<span> exerted on an object . We calculate as follows:
</span>∑F along x = 0 = F - Fn
<span>
Fn = F = mg = 7.52(9.81) = 73.77 N <------OPTION B</span>