R = 18 ohms
Explanation:
Given:
V = 36 volts
I = 2.0 A
R = ?
Use Ohm's law to solve for the resistance:
V = IR
or
R = V/I
= (36 volts)/(2.0 A)
= 18 ohms
Answer:
The new separation distance between adjacent bright fringes will be <u>4 mm</u>
Explanation:
Since, the distance between adjacent bright fringes is given by the formula:
Δx₁ = λL/d = 2 mm -------- eqn (1)
where,
Δx = Distance between adjacent bright fringes
λ = wavelength of light = constant for both cases
L = Distance between the slits and the screen
d = slit separation
Now, for the second case:
Slit Separation = d/2
Therefore,
Δx₂ = λL/(d/2)
Δx₂ = 2(λL/d)
using eqn (1), we get:
Δx₂ = 2 Δx₁
Δx₂ = 2(2 mm)
<u>Δx₂ = 4 mm</u>
The west constituent of their sequence needs to cancel out 58 mph crosswind. Subsequently a northwest direction is a 45-degree angle up to even with the destination. That is the third point out of the triangle and the right angle is at the destination. The top side is the west constituent of their flight the vertical side is their resultant travel and the hypotenuse is their definite distance flown. Since the 58 mph crosswind was negated by flying northwest, the distance from the beginning to the destination must be the same distance as the west component of their travel. The hypotenuse is square root of twice the side since it has 2 identical sides.
c = sqrt (58^2 + 58^2) = sqrt (6728) = 82.02
Alternative solution:
c = sqrt (2) * 58 = 1.414 * 58 = 82.02
Therefore, they have to fly 82.02 mph
