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FinnZ [79.3K]
3 years ago
11

Enumera las funciones del Estado​

Physics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

Gobernancia. ...

Compromiso con el mercado. ...

Seguridad. ...

Infraestructura. ...

Imperio de la ley. ...

Capital humano. ...

Gestión Financiera Pública. ...

Compromiso ciudadano.

Explanation:

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An arrow leaves a bow at 60 m/s at an angle of 30 degrees to the horizon.
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Answer: 11

Explanation:

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A geologist sees a fault along which blocks of rock in the footwall have moved higher relative to blocks of rock in the hanging
Luda [366]

Answer: Normal fault

Explanation:

The type of fault that is explained above is a normal fault. We should note that normal faults typically takes place in a divergent boundary in a scenario where the crusts may have been pulled apart.

Since the crust is pulled apart in this case, it leads to the downward movement of the hanging wall which leads to the football being above the hanging wall.

6 0
3 years ago
Otherwise, Newton's First Law of Motion says that an object will continue to stay at rest or at a _____ until a force is applied
andrezito [222]
Your answer would be motion because u need force to stop motion or anything at that matter
5 0
3 years ago
Read 2 more answers
In Millikan's experiment, an oil drop of radius 1.362 μm and density 0.888 g/cm3 is suspended in chamber C when a downward-point
Misha Larkins [42]

Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

Given;

Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ  X volume of the oil drop

volume of the oil drop (spherical) =  (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

=  (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0
2 years ago
Which of the following are for vector directione?
Inga [223]
Answer:
C. outside 45 degrees
Step-by-step explanation:
C. outside 45 degrees
because it can be any point or direction outside 45 degrees
8 0
2 years ago
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