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Margaret [11]
3 years ago
13

At a large university, 20% of students are enrolled in the nursing program. The dean of students selects a random sample of 20 s

tudents and records n = the number of students enrolled in the nursing program. The dean decides to simulate this random process by using a random number table. He assigns the digits to the outcomes.
1 = student enrolled in nursing program

2–5 = student not enrolled in nursing program

Skip 6–9 and 0

How can the dean use a random number table to simulate one trial of this situation?

He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the mean of the 20 digits.
He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the number of digits that are a 1.
He can select a row of the random number table and read 100 single digits between 1 and 5. He will record the number of digits that are a 1.
He can select a row of the random number table and read 100 single digits between 1 and 5. He will record the percentage of the digits that are a 1.
Mathematics
1 answer:
grin007 [14]3 years ago
3 0

Answer:

He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the number of digits that are a 1.

Step-by-step explanation:

edge 2022

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Describe the ored of operations in this expression find the number it equals.
svlad2 [7]

Answer:

√71

Step-by-step explanation:

Simplify 42÷6 to 7

√64+7

Simplify 64+7 to 71

=√71


8 0
3 years ago
AYUDAAA porfavorrrr primera urna 6 bolas verdes y 3 rojas segunda urna 3 verdes, 3 blancas y 3 rojas tercera urna 6 verdes, 1 bl
marin [14]

We have the following information:

first urn: 6 green balls and 3 red ones

total: 6 + 3 = 9

second urn: 3 green, 3 white and 3 red

total: 3 + 3 + 3 = 9

third urn: 6 green, 1 white and 2 red

total: 6 + 1 + 2 = 9

a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.

b) probability of drawing a green, red and white ball.

first urn:

green = 6/9 = 66.66%

red = 3/9 = 33.33%

white = 0/9 = 0%

second urn:

green = 3/9 = 33.33%

red = 3/9 = 33.33%

white = 3/9 = 33.33%

third urn:

green = 6/9 = 66.66%

red = 2/9 = 22.22%

white = 1/9 = 11.11%

c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%

d) without a green ball, the third ballot box would look like this:

5 green balls, 2 red balls and 1 white ball, with a total of 8.

The probability of drawing would be:

green = 5/8 = 62.5%

red = 2/8 = 25%

white = 1/8 = 12.5%

7 0
3 years ago
Let g be the function given by g(x)=x^2*e^(kx) , where k is a constant. For what value of k does g have a critical point at x=2/
ArbitrLikvidat [17]
G `( x ) =2x * e^{kx}  + k x^{2} *e^{kx} = \\  = xe^{kx}(2 + kx )
2 + k x = 0
k x = -2
k = -2: x = - 2 : 2/3 = - 2 * 3/2
k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3. 
8 0
3 years ago
Jordy looked at a package of M&M's. He realized that 1/3 of the M&M's were blue. 1/4 were red, and 1/8 were yellow. What
DIA [1.3K]

Answer:

blue

Step-by-step explanation:

its blue because the lesser the bigger please hope you get it right

6 0
4 years ago
Consider the following data set:
Komok [63]

Answer:

+5 Range; The range is now 25

Step-by-step explanation:

The original range would be calculated by subtracting 20 from 40, giving you 20 as the range. However, with the point 15 added, there would be a new lowest number, making the new range be 40-15, which is 25.

3 0
3 years ago
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