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Margaret [11]
2 years ago
13

At a large university, 20% of students are enrolled in the nursing program. The dean of students selects a random sample of 20 s

tudents and records n = the number of students enrolled in the nursing program. The dean decides to simulate this random process by using a random number table. He assigns the digits to the outcomes.
1 = student enrolled in nursing program

2–5 = student not enrolled in nursing program

Skip 6–9 and 0

How can the dean use a random number table to simulate one trial of this situation?

He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the mean of the 20 digits.
He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the number of digits that are a 1.
He can select a row of the random number table and read 100 single digits between 1 and 5. He will record the number of digits that are a 1.
He can select a row of the random number table and read 100 single digits between 1 and 5. He will record the percentage of the digits that are a 1.
Mathematics
1 answer:
grin007 [14]2 years ago
3 0

Answer:

He can select a row of the random number table and read 20 single digits between 1 and 5. He will record the number of digits that are a 1.

Step-by-step explanation:

edge 2022

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3 years ago
Which point best represents V26 on the number line below? ​
LiRa [457]

Answer:

Th answer is C u got it right

Step-by-step explanation:

7 0
3 years ago
Dominic considers buying 2 points on a 25-year, fixed rate mortgage for $187,600. His interest rate will be 5.45% if he does not
algol [13]

Answer:

If Dominic buys 2 points (2% of the loan value) he will get a better rate and hence less payment.  The question is asking how long will it take him to save the initial investment of 2% of the loan value due to a smaller payment.  The monthly payment at 5.45% is  $1,146.43,  the monthly payment for 5.2% is  $1,118.66.  This is a difference of  $27.77 per month.  The 2 points will cost him  $3,752.00.  The question is asking how long will it take Dominic to re-coup his  $3,752.00 if he saves $27.77 per month.  Just divide the 2 numbers and you get  135.10 months.  If you divide that by 12 you get 11.26 years, which is roughly 11 years, 4 months.

Step-by-step explanation:

Here is what the question is asking.  If Dominic buys 2 points (2% of the loan value) he will get a better rate and hence less payment.  The question is asking how long will it take him to save the initial investment of 2% of the loan value due to a smaller payment.  The monthly payment at 5.45% is  $1,146.43,  the monthly payment for 5.2% is  $1,118.66.  This is a difference of  $27.77 per month.  The 2 points will cost him  $3,752.00.  The question is asking how long will it take Dominic to re-coup his  $3,752.00 if he saves $27.77 per month.  Just divide the 2 numbers and you get  135.10 months.  If you divide that by 12 you get 11.26 years, which is roughly 11 years, 4 months.

3 0
3 years ago
Rlly need help on this ill give brainliest :)
Maksim231197 [3]

Answer:

3^15/5^16

Step-by-step explanation:

(3^3 x 3^6 x 5^-4) / (3^-6 x 5^12)

= (3^3 x 3^6 x 3^6) / (5^12 x 5^4)

= 3^15 / 5^16

4 0
2 years ago
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
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