Answer:
to get the probability you add the number of figure all together
divide the number of spheres with the total
ie
2 ÷ 10
you get 1÷ 5
you get the answer as 0.2
70. Bobbie wants to make 2.00 dollars using dollars with the value of half dollars and quarters. Now, how many way he can do it?
=> half dollars = 0.5
=> quarter dollars = 0.25
Possible ways:
=> 0.5 + 0.5 + 0.5 + 0.5 = 2 dollars (4 half dollars)
=> .25 + .25 + .25 +. 25 + .25 + .25 + .25 + .25 = 2 dollars (8 quarter dollars)
=> 0.5 + 0.5 + 0.25 + 0.25 + 0.25 + 0.25 = 2 dollars
=> 0.5 + 0.5 + 0.5 + 0.25 + 0.25 = 2 dollars
=> 0.5 + 0.25 + .25 + .25 + .25 + .25 + .25 = 2 dollars
9514 1404 393
Answer:
(a) none of the above
Step-by-step explanation:
The largest exponent in the function shown is 2. That makes it a 2nd-degree function, also called a quadratic function. The graph of such a function is a parabola -- a U-shaped curve.
The coefficient of the highest-degree term is the "leading coefficient." In this case, that is the coefficient of the x² term, which is 1. When the leading coefficient of an even-degree function is positive, the U curve has its open end at the top of the graph. We say it "opens upward." (When the leading coefficient is negative, the curve opens downward.)
This means the bottom of the U is the minimum value the function has. For a quadratic in the form ax²+bx+c, the horizontal location of the minimum on the graph is at x=-b/(2a). This extreme point on the curve is called the "vertex."
This function has a=1, b=1, and c=3. The minimum of the function is where ...
x = -b/(2·a) = -1/(2·1) = -1/2
This value is not listed among the answer choices, so the correct choice for this function is ...
none of the above
__
The attached graph of the function confirms that the minimum is located at x=-1/2
_____
<em>Additional comment</em>
When you're studying quadratic functions, there are few formulas that you might want to keep handy. The formula for the location of the vertex is one of them.
Answer:
52
Step-by-step explanation:
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one