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zhenek [66]
2 years ago
13

Could somebody please solve this for me?

Mathematics
1 answer:
olchik [2.2K]2 years ago
5 0

Check the picture below.

a+b=180\implies b=180-a \\\\\\ \stackrel{\textit{substituting on the 2nd equation}}{a-39=2(180-a)}\implies a-39=360-2a\implies 3a-39=360 \\\\\\ 3a=321\implies a = \cfrac{321}{3}\implies \boxed{a = 107}~\hfill \boxed{\stackrel{180-107}{b = 73}}

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Write the decimal as a fraction in simplest form.​
goblinko [34]

your Answer is going to be 13/25

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2 years ago
The line segment shown is translated down 4 units, what are the new coordinates of B?<br> (0.3)
xxTIMURxx [149]

Answer:

(0, - 1 )

Step-by-step explanation:

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8 0
3 years ago
AWARDING BRAINLIEST!!! Five classmates came to Dan’s birthday party. This is half as many as the number of his summer camp frien
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Answer:

20 people. Because 5 already came to the party. 1/3 of his relatives came is 5, so multiply 5 by 3, then add 5. You get 20 people.

Step-by-step explanation:

5 0
3 years ago
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If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=8/17and cos b=1
n200080 [17]

Recall the sum identity for cosine:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

so that

cos(a + b) = 12/13 cos(a) - 8/17 sin(b)

Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,

cos²(a) + sin²(a) = 1   ⇒   cos(a) = √(1 - sin²(a)) = 15/17

cos²(b) + sin²(b) = 1   ⇒   sin(b) = √(1 - cos²(b)) = 5/13

Then

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6 0
2 years ago
Mr.Williams physical education class lasts 7/8 hour if instruciton is 1/5 how many minutes are not spent on instruction?
g100num [7]
= 7/8 − 1/5

= ((7 × 5) − (1 × 8)) / (8 × 5)

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= 27/40


SO, 27/40 minutes are NOT spend on instructions.
Hope I was able to help! :)
6 0
3 years ago
Read 2 more answers
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