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iVinArrow [24]
3 years ago
6

a compound is found to contain 64% silver *% nitrogen and 28% oxygen by mass what is the empoircal fomula

Chemistry
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

The empirical formula of this compound is AgNO3.

Explanation:

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Phoenix [80]
In 0.25 mole there are 1.5*1023 molecules of 02 since there are 6.02*1023 particles in one mole.
8 0
3 years ago
A reaction that occurs in the internal combustion engine is N₂(g) + O₂(g) ⇄ 2NO(g) (d) At what temperature (in K) does the react
S_A_V [24]

The reaction is spontaneous at a temperature of 7281.4 K

As the value of temperature rises, it is decreasing in accordance with the value of ΔG°, according to the value ofΔG° calculated. The value shifts from being more positive to being less positive. It ΔG°at a certain temperature.

It would appear that the value of would be negative, causing the reaction to occur on its own.

The calculation shown below can be used to determine the temperature at which the reaction starts spontaneously.

ΔG°= ΔH°-TΔS°

ΔG° now equals zero.

0 = 180.58 - T 24.8(1/1000)

T= 180.58/0.0248 K

T=7281.4 K

therefore, the reaction is spontaneous at a temperature of 7281.4 K

Learn more about ΔG° here:

brainly.com/question/17214066

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5 0
2 years ago
Example of gases collected through upward delivery​
fgiga [73]

Answer:

In this process The more dense gases are collected in a gas jar. Carbon dioxide, Nitrogen dioxide are collected by this way. Air is displaced upward thus, this process is known as upward delivery

Hope it helped :)

4 0
3 years ago
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A 7.50-g sample of iron is heated in oxygen to form an iron oxide. if 10.71 g of the oxide is formed, what is its empirical form
Zielflug [23.3K]
Answer is: empirical formula is Fe₂O₃.
m(Fe) = 7,50 g.
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n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 7,50 g ÷ 55,85 g/mol = 0,134 mol.
m(O) = m(iron oxide) - m(Fe).
m(O) = 10,71 g - 7,50 g = 3,21 g.
n(O) = 3,21 g ÷ 16 g/mol = 0,20 mol.
n(Fe) : n(O) = 0,134 mol : 0,2 mol = 2 : 3.
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4 years ago
How do elements on the right side of the periodic table differ from elements on the left side of the table?
lozanna [386]

The answer is c.


Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.


Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

4 0
3 years ago
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