In 0.25 mole there are 1.5*1023 molecules of 02 since there are 6.02*1023 particles in one mole.
The reaction is spontaneous at a temperature of 7281.4 K
As the value of temperature rises, it is decreasing in accordance with the value of ΔG°, according to the value ofΔG° calculated. The value shifts from being more positive to being less positive. It ΔG°at a certain temperature.
It would appear that the value of would be negative, causing the reaction to occur on its own.
The calculation shown below can be used to determine the temperature at which the reaction starts spontaneously.
ΔG°= ΔH°-TΔS°
ΔG° now equals zero.
0 = 180.58 - T 24.8(1/1000)
T= 180.58/0.0248 K
T=7281.4 K
therefore, the reaction is spontaneous at a temperature of 7281.4 K
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Answer:
In this process The more dense gases are collected in a gas jar. Carbon dioxide, Nitrogen dioxide are collected by this way. Air is displaced upward thus, this process is known as upward delivery
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Answer is: empirical formula is Fe₂O₃.
m(Fe) = 7,50 g.
m(iron oxide) = 10,71 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 7,50 g ÷ 55,85 g/mol = 0,134 mol.
m(O) = m(iron oxide) - m(Fe).
m(O) = 10,71 g - 7,50 g = 3,21 g.
n(O) = 3,21 g ÷ 16 g/mol = 0,20 mol.
n(Fe) : n(O) = 0,134 mol : 0,2 mol = 2 : 3.
The answer is c.
Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.
Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.