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Vadim26 [7]
3 years ago
9

Q- 30. The number of grams of solute

Chemistry
1 answer:
pochemuha3 years ago
6 0

Answer:

Mass by mass

Explanation:

Because it's telling only about mass in grams

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Figuring out how to make a better type of plastic is which type of research
quester [9]

Answer:applied chemistry

5 0
3 years ago
Read 2 more answers
A chemistry student measures out 41 grams of sodium hydroxide, NaOH. They react it with an excess of hydrochloric acid, HCl, for
exis [7]
The answer will be around 687.928 grams
8 0
3 years ago
Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an
Bess [88]

In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is 1.68*10^{-4} M.

Explanation:

For the first equlibria;

initial concentration of H_{2}C_{3}H_{2}OH=0.15

initial concentration of HC_{3}H_{2}O_{4}^{-} =0

initial concentration of H^{+} =0

Let concentration change of H_{2}C_{3}H_{2}OH=-x

Let concentration change of HC_{3}H_{2}O_{4}^{-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  H_{2}C_{3}H_{2}OH=0.15-x

Let concentration in equilibrium state ofHC_{3}H_{2}O_{4}^{-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{1}=\frac{x*x}{0.15-x}=\frac{1.5*10^{-3}}{1} =\frac{x^{2}}{0.15-x}

x^{2}+0.0015x-0.000225=0

Which is a quadratic equation in x, solving it gives;

x=0.01427

Therefore, HC_{3}H_{2}O_{4}^{-} =x= 0.01427M

Now for the second equlibria;

initial concentration of HC_{3}H_{2}O_{4}^{-}=0.01427

initial concentration of C_{3}H_{2}O_{4}^{2-} =0

initial concentration of H^{+} =0

Let concentration change of HC_{3}H_{2}O_{4}^{-}=-x

Let concentration change of  C_{3}H_{2}O_{4}^{2-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  HC_{3}H_{2}O_{4}^{-}=0.01427-x

Let concentration in equilibrium state ofC_{3}H_{2}O_{4}^{2-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}

2.854*10^{-8}-(2.0*10^{-6})x=x^{2}

Therefore, C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

4 0
1 year ago
In an experiment, 135.2 grams of a mystery metal is heated to 100.0*C. The metal is then dumped into a calorimeter with 59.0 gra
Rufina [12.5K]
The answer wound be 23 units I think
4 0
3 years ago
PLEASEEEE HELP :')
mel-nik [20]

Answer:

340 grams Ca₃P₂ (2 sig. figs.)

Explanation:

   3Ca     +     2P     =>    Ca₃P₂

5.6 mole + excess =>   ? grams

Convert the 'known' to a coefficient of 1 by dividing all coefficients by 3.

=>  Ca   +   2/3P   =>    1/3Ca₃P₂

From the above, 1 mole of Ca => 1/3 mole Ca₃P₂  

∴ 5.6 mole Ca in an excess of P => 1/3(5.6 mole) Ca₃P₂

=> 1.8666 mol Ca₃P₂ (calculator answer) ≅ 1.9 mol Ca₃P₂

=> 1.9 mole x 182 g Ca₃P₂/mol Ca₃P₂ = 339.73333 grams Ca₃P₂

≅ 340 grams Ca₃P₂ (2 sig. figs.)

7 0
3 years ago
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