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Aloiza [94]
2 years ago
5

I HAVE 6 MORE PAGES ON THIS HUUUUUUGE ASSIGNMENT!! WHO WANTS TO HELP?????????? i have alr done 22 pages!!

Chemistry
2 answers:
torisob [31]2 years ago
8 0

Answer:

it depends on the assignment but im down

Explanation:

Natalija [7]2 years ago
6 0

Answer:

what is it about I can prob help :)

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Which of the following statements regarding glucose is FALSE?a) Glucose is the main component of starch and glycogen.b) Glucose
marishachu [46]

Answer:

The correct option is C.

Explanation:

Carbohydrates are one of the macro molecules that are consumed by living organisms. The end product of carbohydrate is glucose. Glucose is a very important fuel that the body cells used to produce energy, which they use to carry out their daily activities. Glucose is also known as blood sugar and it is the only fuel that living cells can use for the production of ATP. Other food macro molecules such as lipids and proteins can also be converted to glucose if there is a need for that. Glucose is always stored in the body in form of glycogen.

The statement given in option C about glucose is wrong because glucose is a monosaccharide and not a disaccharide.

8 0
3 years ago
This is how platinum appears in the periodic table.A purple box has P t at the center and 78 above. Below it says platinum and b
ozzi

Answer:

3.) 195

Explanation:

Because platinum is 195.079 amu (its on the periodic table)

6 0
2 years ago
Read 2 more answers
1. What is the electron configuration of bromine atom?
Ganezh [65]

Answer:

[Ar] 3d¹⁰ 4s² 4p⁵

Explanation:

........

7 0
2 years ago
Read 2 more answers
Given pH = 8.55 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
Firlakuza [10]

Answer:

Explanation:

The given pH = 8.55

Unknown:

[H₃O⁺] = ?

[OH⁻] = ?

In order to find these unknowns we must first establish some relationship.

                      pH = -log[H₃O⁺]

                   8.55 = -log[H₃O⁺]

                    [H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³

To find the [OH⁻],

                     pH + pOH = 14

                               pOH = 14 - pH = 14 - 8.55

                                pOH = 5.45

              pOH = -log[OH⁻]

               [OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³

The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.

7 0
3 years ago
Chemical Name for Rb2S
Westkost [7]

Answer:

Rubidium Sulfide

Explanation:

The chemical name for Rb2S is Rubidium Sulfide

6 0
2 years ago
Read 2 more answers
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