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dybincka [34]
3 years ago
7

In the equation 2K+ 2H2O ---> 2KOH +H2

Chemistry
1 answer:
Law Incorporation [45]3 years ago
6 0

 The much hydrogen that is  produced   is 0.02 mol  of H₂ (answer  B)

 Explanation

2K +2H₂O→ 2 KOH + H₂

 Use the mole ratio to determine the moles of H₂

 From equation above the  K :H₂  is  2:1

Therefore the moles of H₂ = 0.04 x 1/2 = 0.02  mol  of H₂

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How many hydrogen grams can be obtained if
kipiarov [429]

hi im breanna

Answer:

The mole is simply a very large number that is used by chemists as a unit of measurement.

Explanation:

The mole is simply a very large number,  

6.022

×

10

23

, that has a special property. If I have  

6.022

×

10

23

hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have  

6.022

×

10

23

 

H

2

molecules, I have a mass of 2 gram of hydrogen molecules. If I have  

6.022

×

10

23

 

C

atoms, I have (approximately!) 12 grams.

The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of  

C

, I know, fairly precisely, how many atoms of carbon I have. Given this quantity, I know how many molecules of  

O

2

are required to react with the  

C

, which I could measure by mass or by volume.

5 0
3 years ago
5. A filled balloon has a volume of 5.6 L at 25 ˚C and it is placed into liquid nitrogen at a temperature of -78 ˚C. What is the
Yuri [45]
The answer -103, hope this helps
6 0
3 years ago
When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperatu
expeople1 [14]

Answer:

25.2°C

Explanation:

Given parameters:

Energy applied to the water  = 1000J

Mass of water  = 50g

Final temperature  = 30°C

Unknown:

Initial temperature  = ?

Solution:

To solve this problem, we use the expression below:

            H  = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

     1000  = 50 x 4.184 x (30  -  initial temperature )

     1000  = 209.2(30 - initial temperature)

      4.78  = 30 - initial temperature

      4.78  - 30  = - initial temperature

         Initial temperature  = 25.2°C

7 0
3 years ago
The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
What is 25 °C in °F?
kifflom [539]

Answer:

77°F

Explanation:

(25°C × 9/5) + 32 = 77°F

7 0
3 years ago
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