Ask question

Ask question

All categories

3 years ago

12

2 planets are over 4 million light years away. Explain how you would use a ray of light to determine which planet is farther awa

y. Use DATA to help verify your reasoning.

2 answers:

Sergio039 [100]3 years ago

8 0

Look on google......

grigory [225]3 years ago

4 0

Https://earthsky.org/space/what-is-a-light-year

You might be interested in

A sample of gas isolated from unrefined petroleum contains 90.0% CH4, 8.9% C2H6, and 1.1% C3H8 at a total pressure of 3.34 atm.

Leona [35]

Answer:

The partial pressure of each component of this gas is:

Partial pressure of methane= 3.006 atm

Partial pressure of ethane= 0.29726 atm

Partial pressure of propane= 0.03674 atm

Explanation:

The partial pressure of a gas in a mixture is the pressure that gas would exert if it were alone in the container.

On the other hand, the mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component with the number of moles of all the components present.

Dalton's Law of Partial Pressures states that the partial pressure of each gas is equal to the total pressure of the gas mixture multiplied by the mole fraction of that gas.

The partial pressures then, can be calculated by multiplication of the percents by the total pressure.

So, the partial pressure of each component of this gas is: :

$Partial pressure of methane= \frac{90}{100} *3.34 atm=0.9*3.34 atm$

<u><em>Partial pressure of methane= 3.006 atm</em></u>

$Partial pressure of ethane= \frac{8.9}{100} *3.34 atm=0.089*3.34 atm$

<u><em>Partial pressure of ethane= 0.29726 atm</em></u>

$Partial pressure of propane= \frac{1.1}{100} *3.34 atm=0.011*3.34 atm$

<u><em>Partial pressure of propane= 0.03674 atm</em></u>

7 0

3 years ago

PLEASE explain your answer!!!!

Aleks04 [339]

Answer:

Explanation: confusing

6 0

3 years ago

The two isotopes of chlorine are 3517Cl and 3717Cl. Which isotope is the most abundant?

nikklg [1K]

Answer:

The most abundant isotope is ³⁵Cl₁₇.

Since the average atomic mass of Cl is 35.45 g/mole, so the most abundant one is that one near this number, ³⁵Cl₁₇.

³⁵Cl₁₇ is found by 75 % and ³⁷Cl₁₇ is found by 25 % by a ratio 3:1.

6 0

3 years ago

The reaction described by H2(g)+I2(g)⟶2HI(g) has an experimentally determined rate law of rate=k[H2][I2] Some proposed mechanism

MatroZZZ [7]

Answer:

Mechanism A and B are consistent with observed rate law

Mechanism A is consistent with the observation of J. H. Sullivan

Explanation:

In a mechanism of a reaction, the rate is determinated by the slow step of the mechanism.

In the proposed mechanisms:

Mechanism A

(1) H2(g)+I2(g)→2HI(g)(one-step reaction)

Mechanism B

(1) I2(g)⇄2I(g)(fast, equilibrium)

(2) H2(g)+2I(g)→2HI(g) (slow)

Mechanism C

(1) I2(g) ⇄ 2I(g)(fast, equilibrium)

(2) I(g)+H2(g) ⇄ HI(g)+H(g) (slow)

(3) H(g)+I(g)→HI(g) (fast)

The rate laws are:

A: rate = k₁ [H2] [I2]

B: rate = k₂ [H2] [I]²

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]

<em>Where K' = K1 * K2</em>

C: rate = k₁ [H2] [I]

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]^1/2

Thus, just <em>mechanism A and B are consistent with observed rate law</em>

In the equilibrium of B, you can see the I-I bond is broken in a fast equilibrium (That means the rupture of the bond is not a determinating step in the reaction), but in mechanism A, the fast rupture of I-I bond could increase in a big way the rate of the reaction. Thus, just <em>mechanism A is consistent with the observation of J. H. Sullivan</em>

5 0

3 years ago

At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +

Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(c) A ( g ) + B ( g ) ⟶ C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

4 0

2 years ago