Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
Where is the line...................
(x+2)(x+8) = x^2 +10x +16
(x^2 + 10x + 16)(x-1) = x^3+9x^2+6x-16, so the other dimension is x-1
Answer:
answer35
Step-by-step explanation:
<h2><em>I hope it help</em></h2>
4x - 2y = 14
y = 0.5x -1
Get just one variable on one side for both equations.
4x - 2y = 14 ⇒ 4x = 2y + 14 ⇒ 4x - 14 = 2y
y = 0.5x - 1 ⇒ x - 2 = 2y
Use the transitive property and then solve for x.
x-2 = 4x-14
12 = 3x
x = 4
<em>Edit: Apprently I didn't use substitution. Oops! Sorry...</em>