In what real-life situations might you want to use the modulus operation in a program?
1 answer:
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Answer:
Example 1:
def function(num):
print(num*2)
Example 2:
function(5)
num = 2
function(num)
function(3-1)
Explanation:
Given:
See attachment for complete question
To start with Example (1)
def function(num):
print(num*2)
<em>Note that; the above code segment which doubles the parameter, num could have been any other code</em>
<em />
<em>In Example (1), the parameter is num</em>
For example (2):
We can call the function using:
#1. A value:
function(5)
<em>In #1, the argument is 5; a value</em>
#2. A Variable
num = 2
function(num)
<em>In #2, the argument is num; a variable</em>
#3. An Expression
function(3-1)
<em>In #3, the argument is 3-1; an expression</em>
Answer:
Explanation:
The following code is written in Java. It uses for loops to loop through the array of characters, and uses IF statements to check if the symbols in the expression are balanced. If so it returns true, otherwise it breaks the function and returns false. Two test cases have been provided in the main method and the output can be seen in the attached image below.
import java.util.ArrayList;
class Brainly {
public static void main(String[] args) {
char[] exp = { '[', 'A', '*', '{', 'B', '(', 'C', 'D', ')', '}', ']'};
char[] exp2 = {'[', 'A', '*', '(', 'C', '}', ']'};
System.out.println(checkBalance(exp));
System.out.println(checkBalance(exp2));
}
public static boolean checkBalance(char exp[]) {
ArrayList<Character> symbols = new ArrayList<>();
for (char x: exp) {
if ((x =='[') || (x == '{') || (x == '(')) {
symbols.add(x);
}
if (x ==']') {
if (symbols.get(symbols.size()-1) == '[') {
symbols.remove(symbols.size()-1);
} else {
return false;
}
}
if (x =='}') {
if (symbols.get(symbols.size()-1) == '{') {
symbols.remove(symbols.size()-1);
} else {
return false;
}
}
if (x ==')') {
if (symbols.get(symbols.size()-1) == '(') {
symbols.remove(symbols.size()-1);
} else {
return false;
}
}
}
return true;
}
}
