Answer:
8 grams
Step-by-step explanation:
The balance is in equilibrium, so the weights of the two sides are equal.
Let the weight of a square be s.
Left side: 2s + 4
Right side: s + 3(4) = s + 12
The weights are equal, so we set the two expressions equal.
2s + 4 = s + 12
s = 8
Answer: The weight of a square is 8 grams.
Answer:
x=7 y=3
Step-by-step explanation:
-x+6y=11
2x-3y=5
-2x+12y=22
2x-3y=5
Add both equations
-2x+2x-3y+12=22+5
9y=27
y=3
plug y back in
-x+18=11
-x=-7
x=7
A. 72÷9÷2 = 8÷2 = 4
b. (18 ÷ 6) ÷ 3 = 3 ÷ 3 = 1
c. 45 ÷ 5 ÷ 3 = 9 ÷ 3 = 3
d. 144 ÷ (12 ÷ 2) = 144 ÷6 = 24
he volume of the solid under a surface
z
=
f
(
x
,
y
)
and above a region D is given by the formula
∫
∫
D
f
(
x
,
y
)
d
A
.
Here
f
(
x
,
y
)
=
6
x
y
. The inequalities that define the region D can be found by making a sketch of the triangle that lies in the
x
y
−
plane. The bounding equations of the triangle are found using the point-slope formula as
x
=
1
,
y
=
1
and
y
=
−
x
3
+
7
3
.
Here is a sketch of the triangle:
Intersecting Region
The inequalities that describe D are given by the sketch as:
1
≤
x
≤
4
and
1
≤
y
≤
−
x
3
+
7
3
.
Therefore, volume is
V
=
∫
4
1
∫
−
x
3
+
7
3
1
6
x
y
d
y
d
x
=
∫
4
1
6
x
[
y
2
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
y
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
49
9
−
14
x
9
+
x
2
9
−
1
]
d
x
=
3
∫
4
1
40
x
9
−
14
x
2
9
+
x
3
9
d
x
=
3
[
40
x
2
18
−
14
x
3
27
+
x
4
36
]
4
1
=
3
[
(
640
18
−
896
27
+
256
36
)
−
(
40
18
−
14
27
+
1
36
)
]
=
23.25
.
Volume is
23.25
.
Answer:
Hey the answer is one.
Step-by-step explanation:
There is a quizlet with 18 of the answers with explanations on it just type in the unit subject and this question and it should pop up.
But on a side note,
I don't know who deleted my answer last time but I was giving you a resource to use if you want to learn the full step by step explanation look on your lesson videos or ask your teacher. This site i have found lets people give one another answers so unless this person and some army is planning on stopping everyone from giving answers i think they should just stop using this site.
