Suppose that y varies directly with x, and y=24 when x=15.

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

8 0

Answer:

x=0.625y

y=1.6x

y=3.2

Step-by-step explanation:

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1-116 1.2.6

ankoles [38]

Answer:

A. 30 adults; B. 24 not dolls

Step-by-step explanation:

$\begin{array}{rcl}\text{No. of adults} & = & \text{No. of visitors} \times \text{Fraction who are adults}\\& = & \text{100 visitors} \times \dfrac{\text{3 adults}}{\text{10 visitors}} \\& = & \textbf{30 adults}\\\end{array}$

If five-eighths of the prizes were dolls, then three-eighths of the prizes were not dolls.

$\begin{array}{rcl}\text{No. not dolls} & = & \text{No. of prizes} \times \text{Fraction not dolls}\\& = & \text{64 prizes} \times \dfrac{\text{3 not dolls}}{\text{8 prizes}} \\& = & \textbf{24 not dolls}\\\end{array}$

3 0

3 years ago

X2-7x-18÷x2+8x+12 what is it in lowest terms

Eddi Din [679]

$\dfrac{x^2-7x-18}{x^2+8x+12}=\dfrac{x^2+2x-9x-18}{x^2+6x+2x+12}=\dfrac{x(x+2)-9(x+2)}{x(x+6)+2(x+6)}\\\\=\dfrac{(x+2)(x-9)}{(x+6)(x+2)}=\dfrac{x-9}{x+6}$