Answer:
The question is asking which numbers are larger with respect to one another. An easy way to do this is to convert to decimals, or just memorize it. 1/2=0.5, 3/4=0.75, 2/3=0.666666. So descending order (largest to smallest) 3/4, 2/3, 1/2.
H= .6.5
V=<span>πr^2h
h= v/</span>πr^2 = 2940.5/<span>π*12^2 = 6.49993 = 6.5</span>
Answer:
If your question is -2 - 4 - 2 - 2.1 then the answer is -10.1
Step-by-step explanation:
-2 - 4 - 2 - 2.1
= (-2 - 4 ) - 2 - 2.1 Combine -2 with -4 or subtract them
= -6 - 2 - 2.1
= (-6 - 2 )- 2.1 Combine -6 and -2
= -8 -2.1 Combine -8 and -2.1
= -10.1
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And always,
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SIMPLIFY BANANAS : )</em></u></h3>
Answer:
![\sqrt[5]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B4%7D)
+ ![\sqrt[10]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B3%7D)
Step-by-step explanation:
We sure can write 2^2/5+ 3^1/10 as 
// use the ![a^{\frac{m}{n} } =\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
to transform the expression
Convert 
to ![\sqrt[5]{2^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E%7B2%7D%20%7D)
= (here a = 2, n = 5, m = 2)
Then convert 
to ![\sqrt[10]{3^{1} }](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B3%5E%7B1%7D%20%7D)
= (here a = 3, n = 10, m = 1)
Now we get = + . This is the simplified form, which is the answer.
Answer:
x = 80
Step-by-step explanation:
Because of the parallel lines and the transversal to the left,
x + 67 = 147
x = 80
