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Papessa [141]
2 years ago
9

The rate law for the reaction 3a ⟶⟶ c is rate = 4. 36 x 10–2 l • mol–1 • h–1[ a ]2 how long will it take in hours for the concen

tration of a to decrease from 0. 74 m to 0. 21 m?
Chemistry
1 answer:
Paha777 [63]2 years ago
4 0

The hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

<h3>What is the rate law of a reaction?</h3>

Rate law depicts the rate of a chemical reaction depend on the concentration of the reactant.

The given reaction is second order reaction

Thus, the hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

Learn more about rate law of a reaction

brainly.com/question/8314253

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I am so confused that i don't even understand how to answer it
maksim [4K]

Answer:

What's the question so I can help?

I will just edit my answer when you have asked your question and post it here.

Explanation:

4 0
2 years ago
A pendulum bob at its highest point has a certain amount of potential energy. As it falls, what does the potential energy get tr
Lisa [10]
Good

Because is that true
3 0
3 years ago
Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
arsen [322]

a. mass of iron = 69.92 g

b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

8 0
3 years ago
What was the 'elixir of life' ​
4vir4ik [10]
A magical or medicinal potion/solution
4 0
3 years ago
The molar mass of HgO is 216.59 g/mol. The molar mass of O2 is 32.00 g/mol. How many moles of HgO are needed to produce 250.0 g
Irina-Kira [14]
A reaction in which Oxygen (O₂) is produced from Mercury Oxide (HgO) would be a decomposition reaction.
           2HgO    →    2Hg    +    O₂

If 250g of O₂ is needed to be produced,
then the moles of oxygen needed to be produced = 250g  ÷  32 g/mol
                                                                                     = 7.8125 mol

Now, the mole ratio of Oxygen to Mercury Oxide is  1  :  2
∴ if the moles of oxygen =  7.8125 mol
then the moles of mercury oxide = 7.8125 mol × 2
                                                        = 15.625 mol


Thus the number moles of HgO needed to produce 250.0 g of O₂ is 15.625 mol
 
6 0
3 years ago
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