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sleet_krkn [62]
2 years ago
10

How many moles of nitroglycerin were in the container originally?

Chemistry
1 answer:
Gemiola [76]2 years ago
7 0

Answer:

4.75

Explanation:

I hope this helped!

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How many moles of chlorine gas are in 1.2m^3 at room temperature and pressure?
marshall27 [118]

Answer:

look it up lol

Explanation:

quizlet

5 0
3 years ago
The arrows in the chart below represent phase transitions.
Lana71 [14]

Answer:

a. 1,2,and 3.

Explanation:

When something turns liquid, e.g. metal, you need to heat it. When something turns gas, e.g. water, you need to heat it. And when something goes directly from solid to gas, e.g. dry ice, carbon dioxide, you need to add heat to it. hope this helps! Please mark brainiest.

4 0
3 years ago
How might you add warm water to the beaker of cold water?
Trava [24]
You get a tub of warm water and tip the warm water into the cold water
7 0
3 years ago
Calculate the amount of formula units in 2.10 moles of MgCl₂
Eva8 [605]
MgqI% = the formula and mass for H20 and that should be your answer for water
5 0
3 years ago
Assume that a daily diet of 2000 calories (i.e. 8.37 x 106 J) is converted completely to body heat.
slava [35]

Answer:

(a) the mass of the water is 3704 g

(b) the mass of the water is 199, 285.7 g

Explanation:

Given;

Quantity of heat, H= 8.37 x 10⁶ J

Part (a) mass of water (as sweat) need to evaporate to cool that person off

Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg

H = m x Lvap.

m = \frac{H}{L._{vap}} =\frac{8.37 * 10^6.J}{2.26*10^6\ \frac{J}{kg}} = 3.704 \ kg

mass in gram ⇒ 3.704 kg x 1000g = 3704 g

Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J

specific heat capacity of water, C, 4200 J/kg.°C

H = mcΔθ

where;

Δθ is the change in temperature = 35 - 25 = 10°C

m =\frac{H}{c* \delta \theta} = \frac{8.37 *10^6}{4200*10} = 199.2857 kg

mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g

5 0
3 years ago
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