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amid [387]
3 years ago
6

What is the wavelength of the line corresponding to n=4 in the balmer series? express your answer in nanometers to three signifi

cant figures?
Chemistry
1 answer:
liq [111]3 years ago
8 0
Expression for the Balmer series to find the wavelength of the spectral line is as follows:
1 / λ = R (\frac{1}{2^{2} } -  \frac{1}{ n^{2}} )
Where, λ is wavelength, R is Rydberg constant, and n is integral value (4 here →  Fourth level) 
Substitute 1.097 x 10⁷ m⁻¹ for R and 4 for n in the above equation 
1 / λ = (1.097 x 10⁷ m⁻¹) (\frac{1}{2^{2} } -  \frac{1}{4^{2} }  ) 
   = 0.20568 x 10⁷ m⁻¹
λ = 4.86 x 10⁻⁷ m 
since 1 m = 10⁹ nm
λ = 486 nm 
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How many calories of heat energy are required to melt 20 grams of ice at 0 °c?
Marta_Voda [28]
The latent heat of fusion of ice is 80 calories per gram. This means that if we have 20 grams of ice to be melted from solid to liquid at the freezing point of 0 degrees C, we find the total heat requirement by:
Q = m(Lf) = (20 g)(80 cal/g) = 1600 calories
So the total heat requirement is 1600 calories.
3 0
4 years ago
A logical conclusion based on observations is called an inference.
Roman55 [17]
ANSWER: True
EXPLANATION: An inference is a logical conclusion based on observations.

Hope it helps u!
5 0
3 years ago
Read 2 more answers
When 0.100 mol of carbon is burned in a closed vessel with8.00
antoniya [11.8K]

Answer : The mass of carbon monoxide form can be 2.8 grams.

Solution : Given,

Moles of C = 0.100 mole

Mass of O_2 = 8.00 g

Molar mass of O_2 = 32 g/mole

Molar mass of CO = 28 g/mole

First we have to calculate the moles of O_2.

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{8g}{32g/mole}=0.25moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2C+O_2\rightarrow 2CO

From the balanced reaction we conclude that

As, 2 mole of C react with 1 mole of O_2

So, 0.1 moles of C react with \frac{0.1}{2}=0.05 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and C is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO

From the reaction, we conclude that

As, 2 mole of C react to give 2 mole of CO

So, 0.1 moles of C react to give 0.1 moles of CO

Now we have to calculate the mass of CO

\text{ Mass of }CO=\text{ Moles of }CO\times \text{ Molar mass of }CO

\text{ Mass of }CO=(0.1moles)\times (28g/mole)=2.8g

Therefore, the mass of carbon monoxide form can be 2.8 grams.

5 0
4 years ago
ASAP , 8.81 g Carbon
xz_007 [3.2K]

The empirical formula : C₂Cl₇

The molecular formula : C₁₀Cl₃₅

<h3>Further explanation</h3>

Given

8.81 g Carbon

91.2 g Chlorine

Molar Mass: 1362.5 g/mol

Required

The empirical formula and molecular formula

Solution

Mol ratio :

C = 8.81 g : 12.011 g/mol =0.733

Cl = 91.2 g : 35,453 g/mol = 2..572

Divide by 0.733

C : Cl = 1 : 3.5 = 2 : 7

The empirical formula : C₂Cl₇

(The empirical formula)n = the molecular formula

(C₂Cl₇)n = 1362.5

(2x12.011+7x35.453)n=1362.5

(272.193)n=1362.5

n = 5

6 0
3 years ago
Help please!
umka2103 [35]

Answer: In factories they burn coal under a giant container(a really big gumbo pot pretty much). when the fire is hot enough it starts to boil. When it boils it creates steam and the steam blows on a fan that makes electricity.

4 0
3 years ago
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